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The radius of the 2 ^(nd) orbit of B ^(4...

The radius of the `2 ^(nd)` orbit of `B ^(4+)` ion is

A

4.23 Å

B

0.2340 Å

C

0.4232 Å

D

0.3241 Å

Text Solution

Verified by Experts

The correct Answer is:
C
`"Radius of the nth orbit"(r_n)=0.529xxn^2/ZdotA`
`"For "B^(4+)ion,(Z)=5,"second orbit"(n)=2`
`r_2(B^(4+))=(0.529xx(2)^2)/5dotA=(0.529xx4)/5dotA`
`r_2(B^(4+))=0.432dotA`
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Knowledge Check

  • What would be the radius of second orbit of He^(+) ion ?

    A
    `1.058 A^(@)`
    B
    `3.023 A^(@)`
    C
    `2.068 A^(@)`
    D
    `4.458 A^(@)`

  • The radius of the second Bohr orbit is

    A
    0.053 nm
    B
    0.106 nm
    C
    0.212 nm
    D
    0,0265 nm

  • An electron is revolving in the 2^(nd) orbit of He^+ ion. To this if 12.1 eV of energy supplied. Then to which orbit it will be excited.

    A
    6
    B
    8
    C
    4
    D
    2

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