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Transforming to parallel axes through a ...

Transforming to parallel axes through a point (p,q) the equation `2x^(2)+3xy+4y^(2)+x+18y+25=0` becomes `2x^(2)+3xy+4y^(2)=1`. Then

A

`p=-2,q=3`

B

`p=2,q=-3`

C

`p=2,q=-4`

D

`p=-4,q=3`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • If the axes are transferred to parallel axes through the point (1,-2), then the equation y^(2) -4x +4y+8=0 becomes -

    A
    `y^(2) =4x +1`
    B
    ` y^(2) =4 (x-1)`
    C
    `y^(2) =4 (x+2)`
    D
    `y^(2) =4x`

  • The point of intersection of the straight lines given by the equation 3y^2 - 8xy - 3x^2 - 29x - 3y + 18 = 0 is :

    A
    `(1, 1/2)`
    B
    `(1, -1/2)`
    C
    `(-3/2, 5/2)`
    D
    `(-3/2, -5/2)`

  • If the origin is transferred to the point (-3,2) keeping the axes parallel, then the equation 2x-3y+6=0 becomes-

    A
    `2x' +3y' =6`
    B
    `2x' +3y' +6=0`
    C
    `3x' -2y'=6`
    D
    `2x' -3y' =6`

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    Factorise : 4x^(2)-y^(2)+2x-2y-3xy

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