Consider the differential equation dy/dx...

Consider the differential equation `dy/dx = y/(2ylog y + y -x)`.
Statement - I `xy = y^(2) logy + c ` is a solution of the given differential equation.
Statement - II : The differental equation is a linear equation in y and x.

Statement - I is True, Statement - II is True , Statement - II is a correct explanation for Statement - I

Statement - I is True, Statement - II is True , Statement - II is not a correct explanation for Statement - I

Statement - I is True, Statement - II is False.

Statement - is Fasle, Statement - II is True.

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The solution of the differential equation (dy)/(dx)-y tan x=-2 sinx is -

`y sec x=cos2x+c`

`y sec x=(1)/(2) cos2x+c`

`y cos x=(1)/(2)cos2x+c`

`y cosx=cos2x+c`

`y=ce^(-int P(x)dx)`

`y=ce^(int P(x)dx)`

`y^(-1)=ce^(-int P(x)dx)`

`y^(-1)=ce^(int P(x)dx)`

`xy = C`

`x = Cy^(2)`

`y = Cx`

`y = Cx^(2)`