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In the process AtoBtoC, the change in in...

In the process `AtoBtoC`, the change in internal energy of the system in the steps `AtoB and B to C ` are -x `jK*mol^(-1)` and `ykJ*mol^(-1)`, respectively. What will be the change in internal energy of the system in the step `C toA`?

Text Solution

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`AtoBtoC`
Given, `DeltaU_(AtoB)=-xkJ*mol^(-1) and DeltaU_(BtoC)=ykJ*mol^(-1)`
`therefore DeltaU_(CtoA)=-DeltaU_(AtoC)=(x-y)kJ*mol^(-1)` [since U is a state function,, its change in the forward direction of a process is the same as that in the backward direction but opposite in sign.].
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Knowledge Check

  • Change in internal energy of a system is

    A
    heat absorbed by the system+work is done by the system
    B
    heat liberated by the system+work is done by the system
    C
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    D
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    A
    `x-y-z`
    B
    `x-z+y`
    C
    `y+z-x`
    D
    `y-z-x`

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