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The standard heat of combustion of solid...

The standard heat of combustion of solid naphthalene `[C_(10)H_(8)(s)]` at `25^(@)C` is -5147`kJ*mol^(-1)`. What does it mean?

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At `25^(@)C` , the standard heat of combustion of solid naphthalene `[C_(10)H_(8)(s)]` is -5147 `kJ*mol^(-1)`. This means that at `25^(@)C` and 1 atm presure when 1 mol of solid nephthalene is completely burnt in presence of oxygen, the enthalpy change that occurs is -5147 kJ.
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The standard enthalpy of combustion of C_(x)H_(y)(l) at 25^(@)C is Q kJ*mol^(-1) . Write down the thermochemical equation for the combustion reaction of this compound.

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Knowledge Check

  • Given (at 25^(@)C) : C_(6)H_(6)(g)+(7)/(2)O_(2)(g)to2CO_(2)(g)+3H_(2)O(l),DeltaH^(0)=-1560kJ*mol^(-1) CH_(4)(g)+2O_(2)(g)toCO_(2)(g)+2H_(2)O(l),DeltaH^(0)=-890kJ*mol^(-1) C(s,graphite) +O_(2)(g)toCO_(2)(g),DeltaH^(0)=-393.5kJ*mol^(_1) H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l),DeltaH^(0)=-285.8kJ*mol^(-1) At 25^(@)C if the standard enthalpy of formation of of C_(3)H_(8)(g) is -103.8 kJ *mol^(-1) , then the standard heat of reaction for the reaction: C_(3)H_(8)(g)+H_(2)(g)toC_(2)H_(6)(g)+CH_(4)(g) is-

    A
    `+98.45kJ`
    B
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    C
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    D
    `-47.25kJ`

  • The temperature of a bomb calorimeter changes from 25^(@)C to 32.7^(@)C when w g of naphthalene (molar mass =128g*mol^(-1) ) is burnt completely in the calorimeter. If the heat of combustion at constant volume for naphthalene is -5152kJ*mol^(-1) , then w is (heat capacity of the calorimeter =8.19kJ*K^(-1) )-

    A
    0.87 g
    B
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    C
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    D
    1.57 g

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