Home
Class 12
CHEMISTRY
For the process H(2)O(l)hArrH(2)O(g),Del...

For the process `H_(2)O(l)hArrH_(2)O(g),DeltaH=40.8kJ*mol^(-1)` at the boiling poinit of water. Calculate molar entropy change for vaporisation from liquid phase.

Text Solution

Verified by Experts

Molar entropy change for vaporisation `DeltaS=(DeltaH_("vap"))/(T_(b))`
Given `DeltaH_("vap")=40.8kJ*mol^(-1),` for water `T_(b)=373K`,
`therefore DeltaS=(40.8xx10^(3))/(373)=109.38J*K^(-1)*mol^(-1)`
`therefore `Molar entropy change for vaporisation of water
`=109.38J*K^(-1)*mol^(-1)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CHEMICAL THERMODYNAMICS

    CHHAYA PUBLICATION|Exercise SOLVED NCERT EXERCISE|22 Videos

  • CHEMICAL THERMODYNAMICS

    CHHAYA PUBLICATION|Exercise HIGHER ORDER THINKING SKILLS (HOTS) QUESTIONS|20 Videos

  • CHEMICAL THERMODYNAMICS

    CHHAYA PUBLICATION|Exercise QUESTION ANSWER ZONE FOR BOARD EXAMINATION (SHORT ANSWER TYPE)|35 Videos

  • CHEMICAL KINETICS

    CHHAYA PUBLICATION|Exercise EXERCISE (NUMERICAL PROBLEMS)|37 Videos

  • CHEMISTRY IN EVERYDAY LIFE

    CHHAYA PUBLICATION|Exercise PRACTICE SET 15|15 Videos
Home
Profile