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In case of a gaseous reaction, the diffe...

In case of a gaseous reaction, the different between the heat change at constant volume and the heat change at constant pressure is 2RT. Find out the ratio of `K_(p)` to `K_(c)` of that reaction.

Text Solution

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For any reaction, the heat change at constant volume is `DeltaU` and the heat change at constant pressure is `DeltaH`.
AS given in the question, `DeltaU-DeltaH=2RT`
We know, `DeltaH=DeltaU+DeltanRT`
Therefore, `-DeltanRT=2RT or, Deltan=-2`
Again, `K_(p)=K_(c)(RT)^(Deltan)`
Since, `Deltan=-2,K_(p)=(RT)^(-2) or, (K_(p))/(K_(c))=(1)/((RT)^(2))`.
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