We know, `DeltaG^(0)=-RTlnK_(c) and DeltaG^(0)=-RTlnK_(p)`. State whether the value of `DeltaG^(0)` will be same or not provided the numerical values of both `K_(p) and K_(c)` are different.

Explanation

The values of `DeltaG^(0)` will be different. If the numerical values of `K_(p) and K_(c)` differ, then the value of `DeltaG^(0)` will also be Different because for `K_(p)` and `K_(c)` the corresponding standard states are different in the given two cases. When `DeltaG^(0)=-RTlnK_(c)`. the concentrations of all the reactants and products are taken as 1(M) at standard states. Alternatively, when `DeltaG^(0)=-RTlnK_(p)`, the partial pressures of all the reactants and products at standard states are taken as 1 atm.