Home
Class 12
CHEMISTRY
Arrange the following metals in the orde...

Arrange the following metals in the order in whiCHM they displace eaCHM other from the solution of their salts. `Al, Cu, Fe, Mg, ` and `Zn`.

Text Solution

Verified by Experts

A metal with a smaller standard electrode potential displaces the one with a higher electrode potential from a solution of its salt. Therefore the order is :
`Mg gt Al gt Zn gt Fe gt Cu gt Ag.`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    CHHAYA PUBLICATION|Exercise HIGHER ORDER THINKING SKILL (HOTS) QUESTIONS|30 Videos
  • ELECTROCHEMISTRY

    CHHAYA PUBLICATION|Exercise ADVANCED LEVEL NUMERICAL BANK|38 Videos
  • ELECTROCHEMISTRY

    CHHAYA PUBLICATION|Exercise SOLVED NCERT TEXTBOOK PROBLEMS (NCERT INTEXT QUESTIONS)|25 Videos
  • D - AND F - BLOCK ELEMENTS

    CHHAYA PUBLICATION|Exercise PRACTICE SET 8 (Answer the following questions)|10 Videos
  • ENVIRONMENTAL CHEMISTRY

    CHHAYA PUBLICATION|Exercise PRACTICE SET 14(Answer the following questions)|6 Videos

Similar Questions

Explore conceptually related problems

Arrange the following elements in the increasing order of their first ionisation enthalpy : Li, Be, Na, Mg.

Arrange the following in the order of their location from periphery to centre in the entire dicotyledonous plant body

Arrange the following elements in the increasing order of their first ionisation enthalpy. Li, Be, Na, Mg.

Arrange the following ions in order of their condutances in aqueous solution : Rb^(+), Na^(+),Li^(+)

Arrange the following elements in the increasing order of metallic character: Si, Be, Mg, Na, P

Give reasons for the following . Copper displaces silver from AgNO_(3) solution .

Arrange the following elements in the increasing order of non-metallic character: B, C, Si, N, F.

Arrange the following metal oxides in terms of ascending order of basicity. ZnO, MgO, CaO, CuO.

CHHAYA PUBLICATION-ELECTROCHEMISTRY-SOLVED NCERT TEXTBOOK PROBLEMS (NCERT EXERCISE QUESTIONS)
  1. Arrange the following metals in the order in whiCHM they displace eaCH...

    Text Solution

    |

  2. Given : K^(+)|K=-2.79V, Ag^(+)|Ag=0.80V, Hg^(2+)|Hg=0.79V, Mg^(2+)|M...

    Text Solution

    |

  3. Depict the galvanic cell in which the reqaction Zn(s)+2Ag^(+)(aq)rarr ...

    Text Solution

    |

  4. Zn(s)+ Cu^(2+) rarr Zn^(2+) +Cu(s) in this reaction which is oxidant a...

    Text Solution

    |

  5. Depict the galvanic cell in which the reaction Zn(s)+2Ag^(+)(aq)rarr Z...

    Text Solution

    |

  6. Calculate the standard cell potentials of the galvanic cells in which ...

    Text Solution

    |

  7. Calculate the standard cell potentials of the galvanic cells in which ...

    Text Solution

    |

  8. Write the Nernst equation & EMF of the cells at 298 K : Mg(s)|Mg^(2+...

    Text Solution

    |

  9. Write the Nernst equation & EMF of the cells at 298 K : Fe(s)|Fe^(2...

    Text Solution

    |

  10. Write the Nernst equation & EMF of the cells at 298 K : Sn(s)|Sn^(2...

    Text Solution

    |

  11. Write the Nernst equation & EMF of the cells at 298 K : Pt(s)|Br(2)...

    Text Solution

    |

  12. In the button cells widely used in watches and other devices the follo...

    Text Solution

    |

  13. Define conductivity and moiar conductivity for the solution of an elec...

    Text Solution

    |

  14. The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S.cm^(-1...

    Text Solution

    |

  15. The resistance of a conductivity cell containing 0.001M KCl solution a...

    Text Solution

    |

  16. The conductivity of sodium chloride at 298 K has been determined at di...

    Text Solution

    |

  17. Conductivity of 0.00241M acetic acid solution is 7.896xx10^(-5)S.cm^(-...

    Text Solution

    |

  18. How much charge is required for the following reductions : 1 mol of...

    Text Solution

    |

  19. How much charge is required for the following reductions : 1 mol of...

    Text Solution

    |

  20. How much charge is required for the following reductions : 1 mol of...

    Text Solution

    |