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A aqueous solution of NaCl on electrolys...

A aqueous solution of `NaCl` on electrolysis gives `H_(2)(g), Cl_(2)(g)`, and `NaOH` according to the reaction :
`2Cl^(-)(aq)+2H_(2)Orarr 2OH^(-)(aq)+H_(2)(g)+Cl_(2)(g)`
A direct current of 25A with `62%` efficiency is passed through 20 L NaCl solution (`20%` by weight). (2) How long will it take to form 1kg `Cl_(2)`?

Text Solution

Verified by Experts

According to Faraday's first law, `W=ZIt" …(1)"`
Current efficiency `=62%=0.62`
Effective electric current (I) `=25xx0.62A`
Mass of `Cl_(2)=10^(3)g therefore" Z for "Cl_(2)=("eq. weight")/(96500)=(35.5)/(96500)`
`"Substituting in equation (1), "10^(3)=(35.5)/(96500)xx25xx0.62xxt`
`"or, "t=(10^(3)xx96500)/(35.5xx25xx0.62)="175375.83 sec = 48.71 hrs"`
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A aqueous solution of NaCl on electrolysis gives H_(2)(g), Cl_(2)(g) , and NaOH according to the reaction : 2Cl^(-)(aq)+2H_(2)Orarr 2OH^(-)(aq)+H_(2)(g)+Cl_(2)(g) A direct current of 25A with 62% efficiency is passed through 20 L NaCl solution ( 20% by weight). (1) Give the reaction occurring at anode and cathode.

A aqueous solution of NaCl on electrolysis gives H_(2)(g), Cl_(2)(g) , and NaOH according to the reaction : 2Cl^(-)(aq)+2H_(2)Orarr 2OH^(-)(aq)+H_(2)(g)+Cl_(2)(g) A direct current of 25A with 62% efficiency is passed through 20 L NaCl solution ( 20% by weight). (3) What will be the molarity of the solution with respect to OH^(-) ? (Assume no loss due to evaporation)

Knowledge Check

  • In the reaction, H_2(g) + Cl_2(g) iff 2HCl(g)

    A
    `K_p ne K_c`
    B
    `K_p = K_c`
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    A
    `Delta H = Delta E `
    B
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