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The standard reduction potential of the ...

The standard reduction potential of the half - cell:
`NO_(3)^(-)(aq)+2H^(+)+e rarr NO_(2)(g)+H_(2)O` is `0.78V.`
(1) Calculate the reduction potential in 8 M `H^(+)`.

Text Solution

Verified by Experts

Reaction :
`NO_(3)^(-)(aq)+2H^(+)(aq)+e rarr NO_(2)(g)+H_(2)O(l)`
`E_("cell")=E_("cell")^(@)-(0.059)/(n)log.([NO_(2)][H_(2)O])/([NO_(3)^(-)][H^(+)]^(2))`
`=0.78-(0.059)/(1)log.(1xx1)/(1xx(8)^(2))=0.887V`
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The standard reduction potential of the half - cell: NO_(3)^(-)(aq)+2H^(+)+e rarr NO_(2)(g)+H_(2)O is 0.78V. (2) What will be the reduction potential of the half - cell in neutral solution? Assume all other species has unit concentration.

The standard reduction potential of the following reaction at 25^(@)C, is 0.78V, NO_(3)^(-)(aq)+2H^(+)(aq)+e rarr NO_(2)+H_(2)O. (i) If the concentration of H^(+) is 8(M), what will be the standard reduction potential of the half - cell ? (ii) What will be the reduction potential of the half - cell in neutral solution? Suppose all other constituents are at unit concentration.

Knowledge Check

  • The reduction potential of the electrode Pt|H_(2)("g, 2 atm")|H^(+)(aq, pH=3) is -

    A
    `+0.177V`
    B
    `-0.185V`
    C
    `-0.162V`
    D
    `+0.185V`

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