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The rate constants of reaction at 500K a...

The rate constants of reaction at 500K and 700K are `0.02s^(-1) and 0.07s^(-1)` respectively. Calculate the values of `E_(a) and A.`

Text Solution

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`log.(k_(2))/(k_(1))=(E_(a))/(2.303R)[(T_(2)-T_(1))/(T_(1)T_(2))]`
`thereforeE_(a)=2.303Rxx[(T_(1)T_(2))/(T_(2)-T_(1))]log.(k_(2))/(k_(1))`
`=2.303xx8.314xx[(500xx700)/(200)]log.(0.07)/(0.02)=18230.36J`
Since, `k="Ae"^(-E_(a)//RT)`
`thereforeA=(k)/(e^(-E_(a)//RT))=(0.02)/(e^(-18230//500xx8.314))=1.61s^(-1)`
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