Deduce the molecular shape of `BrF_(3)` on the basis of VSEPR theory.

Explanation

In `BrF_(3)` molecule, the central Br-atom has seven electrons in the valence shell. Three of these will form electron-pair bonds with the three fluorine atoms. Thus there are three bond pairs and two lone pairs of electrons. According to VSEPR theory, these will occupy the corners of a trigonal bipyramid. The two lone pairs will occupy the equatorial positions to minimise lone pair-lone pair and the bond pair-bond pair repulsions. In addition, the axial fluorine atoms will be bent towards the equatorial fluorine in order to minimise the lone pair-lone pair repulsions. Therefore, the shape would be that of a slightly bent 'T'.