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For the first row transition metals the ...

For the first row transition metals the `E^(0)` values are :
`|{:(E^(0),V,Cr,Mn,Fe,Co,Ni,Cu),((M^(2+)|M),-1.18,-0.91,-1.18,-0.44,-0.28,-0.25,+0.34):}|`
Explain the irregularity in the above values.

Text Solution

Verified by Experts

The `E^(0)(M^(2+)|M)` value of a metal is related to the sum of
(i) sublimation energy and ionisation energy of the metal and
(ii) the hydration energy of the metal ion. The irragularity in the `E^(0)(M^(2+)|M)` values of the first row transition metals is due to irregular variation of ionisation enthalpies `(IE_(1)+IE_(2))` and also the sublimation enthalpies.
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For first row transition metals, E^(0) values are irregular - explain.

For M^(2+)|M and M^(3+)|M^(2+) systems the E^(0) values for some metals are as follows : {:(Cr^(2+)"|"Cr,,-0.9V,,Cr^(3+)|Cr^(2+),,-0.4V),(Mn^(2+)"|"Mn,,-1.2V,,Mn^(3+)|Mn^(2+),,+1.5V),(Fe^(2+)"|"Fe,,-0.4V,,Fe^(3+)|Fe^(2+),,+0.8V):} Use this data to comment upon : the stability of Fe^(3+) in acid solution as compared to that of Cr^(3+) or Mn^(3+)

For M^(2+)|M and M^(3+)|M^(2+) systems the E^(0) values for some metals are as follows : {:(Cr^(2+)"|"Cr,,-0.9V,,Cr^(3+)|Cr^(2+),,-0.4V),(Mn^(2+)"|"Mn,,-1.2V,,Mn^(3+)|Mn^(2+),,+1.5V),(Fe^(2+)"|"Fe,,-0.4V,,Fe^(3+)|Fe^(2+),,+0.8V):} Use this data to comment upon : the ease with which iron can be oxidised as compared to a similar process for either chromium or manganese metal.

Can Fe^(2+) be produced in the reaction of Fe with 1(M) HCl solution? Explain. Given : E_(Fe^(2+)|Fe)^(@)=-0.44V

The standard reduction potentials of Ni^(2+)|Ni, Cr^(3+)|Cr, Ag^(+)|Ag, Fe^(2+)|Fe electrodes are -0.24, -0.74, +0.80 and -0.44V , respectively. Arrange Ni, Cr, Ag and Fe in increasing order of their reducing power and give reasons.

If Fe is allowed to react with 1(M) HCl solution, will Fe be oxidised to Fe^(2+)? E_(Fe^(+2)|Fe)^(@)=-0.44V

Calomel electrode is represented as - Hg(l)|Hg_(2)Cl_(2)(s)|HCl(aq), Its E^(@) value is +0.24V . When it is connected to Cu|Cu^(2+)(1M) electrode (E^(@)=+0.34V) , what chemical reaction occurs at the calomel electrode?

At 25^(@)C , the reduction potential of Cu^(2+)|Cu half - cell is 0.28V. If E^(@) of Cu^(2)|Cu half-cell is +0.34V , find the molar concentration of Cu^(2+) ion in the half - cell.

Four successive members of the first row transition elements are listed below with atomic numbers. Which one of them is expected to have the highest E_(M^(3+)|M^(2+))^(0) value -

Between Fe and Mn which can be converted to +2 oxidation state easily ? Given : E_(Fe^(2+)|Fe)^(@) =-0.44" V & "E_(Mn^(2+)|Mn)^(@)= - 1.20 V

CHHAYA PUBLICATION-D - AND F - BLOCK ELEMENTS -SOLVED NCERT TEXTBOOK PROBLEMS (NCERT INTEXT QUESTIONS)
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  13. Which of the 3d-series of the transition metals exhibits the largest n...

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  14. The E^(0)(M^(2+)|M) value for copper is positive (+0.34V). What is pos...

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  15. How would you account for the irregular variation of ionisation enthal...

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  16. Why is the highest oxidation state of a metal exhibited in its oxide o...

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  17. Which is a stronger reducing agent Cr^(2+) or Fe^(2+) & Why ?

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  18. Calculate the 'spin only' magnetic moment of M^(2+)(aq) ion (Z = 27).

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  19. Explain why Cu^(+) ion is not stable in aqueous solutions.

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  20. Actinoid contraction is greater from element to element than lanthanoi...

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