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For the first row transition metals the ...

For the first row transition metals the `E^(0)` values are :
`|{:(E^(0),V,Cr,Mn,Fe,Co,Ni,Cu),((M^(2+)|M),-1.18,-0.91,-1.18,-0.44,-0.28,-0.25,+0.34):}|`
Explain the irregularity in the above values.

Text Solution

Verified by Experts

The `E^(0)(M^(2+)|M)` value of a metal is related to the sum of
(i) sublimation energy and ionisation energy of the metal and
(ii) the hydration energy of the metal ion. The irragularity in the `E^(0)(M^(2+)|M)` values of the first row transition metals is due to irregular variation of ionisation enthalpies `(IE_(1)+IE_(2))` and also the sublimation enthalpies.
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For first row transition metals, E^(0) values are irregular - explain.

For M^(2+)|M and M^(3+)|M^(2+) systems the E^(0) values for some metals are as follows : {:(Cr^(2+)"|"Cr,,-0.9V,,Cr^(3+)|Cr^(2+),,-0.4V),(Mn^(2+)"|"Mn,,-1.2V,,Mn^(3+)|Mn^(2+),,+1.5V),(Fe^(2+)"|"Fe,,-0.4V,,Fe^(3+)|Fe^(2+),,+0.8V):} Use this data to comment upon : the stability of Fe^(3+) in acid solution as compared to that of Cr^(3+) or Mn^(3+)

Knowledge Check

  • Four successive members of the first row transition elements are listed below with atomic numbers. Which one of them is expected to have the highest E_(M^(3+)|M^(2+))^(0) value -

    A
    Cr (Z = 24)
    B
    Mn (Z = 25)
    C
    Fe (Z = 26)
    D
    Co (Z = 27)

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