(b) Determine the hybridisation of the central metal ion. `[Fe(C_(2)O_(4))(H_(2)O)_(4)]_(2)SO_(4)`
Text Solution
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Here, the oxidation state of Fe is `+3` and the donor atom is O. Thus, it forms high spin octahedral complex. Hence, the hybridisation of `Fe^(3+)` ion in this compound is `sp^(3)d^(2)`.
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(a) Write down the IUPAC name of [Fe(C_(2)O_(4))(H_(2)O)_(4)]_(2)SO_(4) .
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In the balanced equation for the reaction H_(2)SO_(4)+xHItoH_(2)S+yl_(2)+zH_(2)O
Calculate the oxidation number of the central metal atom or ion for the following : (i) [Cr(C_(2)O_(4))_(3)]^(3-)
Detemine the equivalent mass of Fe _(2)O_(4) in the given reaction : Fe_(2)O_(4)+KmnO_(4)toFe_(2)O_(3)+MnO_(2) (Assume that the molecular mass of Fe_(3)O_(4)=M ]
In the following oxidation half- reaction gives - 2KMnO_(4)+5H_(2)C_(2)O_(4)+3H_(2)SO_(4)toK_(2)SO_(4)+2MnSO_(4)+10CO_(2)+8H_(2)O
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Knowledge Check
In the balanced equation for the reaction H_(2)SO_(4)+xHItoH_(2)S+yl_(2)+zH_(2)O
A
x=y
B
y=z
C
x=2y
D
z=2x
In the following oxidation half- reaction gives - 2KMnO_(4)+5H_(2)C_(2)O_(4)+3H_(2)SO_(4)toK_(2)SO_(4)+2MnSO_(4)+10CO_(2)+8H_(2)O
A
`MnSO_(4)`
B
`CO_(2)`
C
`K_(2)SO_(4)`
D
`H_(2)O`
CHHAYA PUBLICATION-COORDINATION COMPOUNDS OR COMPLEX COMPOUNDS-PRACTICE SET 21
