The ionic radii of `Rb^(+)` and `Br^(-)` ions are 147 pm and and 195 pm resectively. Deduce the possible C.N of `Rb^(+)` ions in RbBr

Answer

8

Explanation

Radius ratio `(r^(+)//r^(-))=(("147pm"))/(("195pm"))=0.753`
`therefore` The possible C.N. of `Rb^(+)` ion in RbBr = 8.