Home
Class 12
CHEMISTRY
An element crystallises in f.c.c. lattic...

An element crystallises in `f.c.c.` lattice having edge length `400 p m`. Calculate the maximum diameter, which can be placed in interstitial sites without disturbing the structure.

Text Solution

Verified by Experts

For a fcc structure, edge length (a) is related to the radius (r)
`r=(a)/(2sqrt2)=((400"pm")/(2sqrt2))=141.42"pm"`
In octahedral (fcc) void R = 0.414 r
`=0.414xx141.42`
Diameter `=2R=2xx0.414xx141.42=117.096"pm."`
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    DINESH PUBLICATION|Exercise PROBLEMS|71 Videos

  • SOLID STATE

    DINESH PUBLICATION|Exercise MULTIPLE CHOCIE QUESTION (TYPE-I)|63 Videos

  • SOLID STATE

    DINESH PUBLICATION|Exercise QUESTION FROM BOARD EXAMINATION|80 Videos

  • REDOX REACTIONS

    DINESH PUBLICATION|Exercise Ultimate Preparation|9 Videos

  • SOLUTIONS

    DINESH PUBLICATION|Exercise ULTIMATE PREPARATORY PACKAGE|10 Videos

Similar Questions

Explore conceptually related problems

An element crystallises in fee lattice having edge length 350 Maximum raduis of the atoms which can be placed in the internal site without distoring the structure is

A metal crystallizes in fcc arrangement with edge length equal to 400 nm. Calculate maximum possible radius of the atom which can fit in the voids without disturbing the crystal structure?

An element crystallises in a f.c.c. lattice with edge length of 400 pm. Calculate the density if 200 g of this element contain 2.5xx10^(24) atoms.

What would be the edge length of that fcc unit cell in which an atom with maximum diameter 117.1 pm can be placed in between its interstitial sites without changing its structure ?

In face - centred cubic (fcc) crystal lattice, edge length is 400 pm. Find the diameter of the greatest sphere which can be fitted into the interstital void without distortion of the lattice.

A metal crystallises in b.c.c. lattice. The per cent fraction of edge length not covered by atom is :