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The metal calcium crystallises in fcc un...

The metal calcium crystallises in fcc unit cell with a = 600 pm. Calculate the density of the metal if it contains `0.2%` Schottky defects.

Text Solution

Verified by Experts

The correct Answer is:
`2.05"g cm"^(-3)`
Due to Schottky defects, the number of atoms per unit cell will decrease.
`Z=(4-(4xx0.2)/(100))=(4-0.008)=3.992`
Density `(rho)=(ZxxM)/(a^(3)xxN_(0)xx10^(-30))`
`=((3.992)xx(40gmol^(-1)))/((600)^(3)xx(6.022xx10^(23)mol^(-1))xx(10^(-30)cm^(3)))`
`=2.05g cm^(-3)`
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A metal crystallizes in a face centred cubic unit cell with a = 0.560 nm . Calculate the density of the metal if it contains 0.1% Schottky defects. (Atomic mass of metal = 40 g mol^(-1))

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Knowledge Check

  • Calcium crystallizes in a face centred cubic unit cell with a = 0.560 nm. The density of the metal if it contains 0.1% schottky defects would be:

    A
    `1.51gcm^(-3)`
    B
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    C
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    D
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  • Calcium crystallises in a face - centred cubic unit cell with a=556nm . Calculate the density if it contained 0.1% Vaccancy defects.

    A
    `1.90 g//cm^(3)`
    B
    `1.54g//cm^(3)`
    C
    `3.4g//cm^(3)`
    D
    `5.4g//cm^(3)`

  • Calcium metal crystallises in fcc lattice with edge length of 556 pm. Calcualte the density in g//cm^(3) ) of metal if it contains 0.2% Schottky defects.

    A
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    B
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    C
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    D
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