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From the following bond energies :- H-...

From the following bond energies :-
`H-H "bond energy" = 420 KJmol^(-1)`
`C=-c "bond energy" = 601 KJmol^(-1)`
`C-C "bond energy"=340KJmol^(-1)`
`C-H "bond energy" = 425 KJ mol^(-1)`
Enthalpy for the reaction :-
`C_(2)H_(2)+2H_(2)toC_(2)H_(6)`

A

`-599 KJ mol^(-1)`

B

`-580 KJ mol^(-1)`

C

`-625 KJ mol^(-1)`

D

`-325 KJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

`DeltaH_(rxn)=2B.E(C-H)+B.E(C-=C)+2B.E(H-H)-6B.E(C-H)-B.E(C-C)`
`rArrB.E(C-=C)+2B.E(H-H)-4B.E(C-H)-B.E(C-C)`
`rArr 601+2xx240-4xx425-340`
`DeltaH_(rxn=-599KJ//mol`
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Find the enthalpy of formation of Hydrogen fluoride on the basis of following data : Bond energy of H-H bond = 434kJ mol^(-1) Body energy of F-F bond = 158 kJ mol^(-1) Bond energy of H-F bond = 565 kJ mol^(-1)

Knowledge Check

  • From the following bond energies: H--H bond energy: 431.37KJmol^(-1) C=C bond energy: 606.10KJmol^(-1) C--C bond energy: 336.49KJmol^(-1) C--H bond energy: 410.50KJmol^(-1) Enthalpy for the reaction will be: overset(H)overset(|)underset(H)underset(|)(C)=overset(H)overset(|)underset(H)underset(|)(C)+H-H to Hoverset(H)overset(|)underset(H)underset(|)(C)-overset(H)overset(|)underset(H)underset(|)(C)-H

    A
    `553.0KJmol^(-1)`
    B
    `1523.6KJmol^(-1)`
    C
    `-243.6KJmol^(-1)`
    D
    `-120.0KJmol^(-1)`

  • From the following bond energies H-H bond energy : 431.37 kJ mol^(-1) C=C bond energy : 606.10 kJ mol^(-1) C-C bond energy : 336.49 kJ mol^(-1) C-H bond energy : 410.50 kJ mol^(-1) Enthalpy for the reaction. underset(H)underset(|)overset(H)overset(|)(C)=underset(H)underset(|)overset(H)overset(|)(C)+H-HrarrH-underset(H)underset(|)overset(H)overset(|)(C)-underset(H)underset(|)overset(H)overset(|)(C)-H will be

    A
    1523.6 kJ `mol^(-1)`
    B
    `-243.6 kJ mol^(-1)`
    C
    `-120.0 kJ mol^(-1)`
    D
    553.0 kJ `mol^(-1)`

  • From the following bond energies: H-H bond enerwgy: 431.37 kJ mol^(-1) C=C bond energy: 606.10 kJ mol^(-1) C-C bond energy: 336.49 kJ mol^(-1) C-H bond energy: 410.50 kJ mol^(-1) Enthalpy for the reaction, underset(H)underset(|)overset(H)overset(|)(C)=underset(H)underset(|)overset(H)overset(|)(C)+H-HtoH-underset(H)underset(|)overset(H)overset(|)(C)-underset(H)underset(|)overset(H)overset(|)(C)-H will be

    A
    `-243.6kJ" "mol^(-1)`
    B
    `-120.0kJ" "mol^(-1)`
    C
    `553.0kJ " "mol^(-1)`
    D
    `5123.6kJ " "mol^(-1)`

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