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The fraction of total volume ocupied by ...

The fraction of total volume ocupied by the atoms present in FCC is :-

A

`(pi)/(6)`

B

`(pi)/(3sqrt2)`

C

`(pi)/(4sqrt2)`

D

`(pi)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • The fraction of total volume occupied by the atoms present in a simple cube is

    A
    `pi/(3sqrt2)`
    B
    `pi/(4sqrt2)`
    C
    `pi/4`
    D
    `pi/6`

  • The fraction of the total volume occupied by the atoms present in a simple cube is

    A
    `pi//4`
    B
    `pi//6`
    C
    `pi/3sqrt2`
    D
    pi/4sqrt2`

  • The fraction of the total volume occupied by the atoms present in a simple cube is

    A
    `pi/4`
    B
    `pi/6`
    C
    `pi/sqrt(3sqrt2)`
    D
    `pi/sqrt(4sqrt2)`

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