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The weight of copper (At wt = 63.5) disp...

The weight of copper (At wt = 63.5) displaced by a quantity of electricity which displaces 5600 ml of `O_(2)` at STP will be :-

A

63.5 g

B

31.5 g

C

15.875 g

D

127 g

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the weight of copper displaced by the quantity of electricity that displaces 5600 ml of O₂ at STP, we can follow these steps: ### Step 1: Calculate the number of moles of O₂ At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22,400 ml. Therefore, the number of moles of O₂ can be calculated using the formula: \[ \text{Number of moles of O}_2 = \frac{\text{Volume of O}_2}{\text{Volume at STP}} = \frac{5600 \, \text{ml}}{22400 \, \text{ml/mol}} = 0.25 \, \text{moles} \] ### Step 2: Calculate the equivalent weight of O₂ The equivalent weight of O₂ can be calculated as follows: \[ \text{Equivalent weight of O}_2 = \frac{\text{Molar mass of O}_2}{4} = \frac{32 \, \text{g/mol}}{4} = 8 \, \text{g/equiv} \] ### Step 3: Calculate the total charge (Q) using Faraday's law Using Faraday's law, we can relate the weight of oxygen displaced to the charge: \[ W = \text{Equivalent weight} \times \text{Number of moles} = 8 \, \text{g/equiv} \times 0.25 \, \text{moles} = 2 \, \text{g} \] Using the formula \( W = Z \times Q \), where \( Z \) is the equivalent weight and \( Q \) is the charge, we can rearrange to find \( Q \): \[ Q = \frac{W}{Z} \times 96500 = \frac{2 \, \text{g}}{8 \, \text{g/equiv}} \times 96500 = 24125 \, \text{C} \] ### Step 4: Calculate the equivalent weight of copper The equivalent weight of copper (Cu) can be calculated as follows: \[ \text{Equivalent weight of Cu} = \frac{\text{Atomic weight of Cu}}{2} = \frac{63.5 \, \text{g/mol}}{2} = 31.75 \, \text{g/equiv} \] ### Step 5: Calculate the weight of copper displaced (W) Now we can use the charge calculated in Step 3 to find the weight of copper displaced: \[ W = Z \times Q = 31.75 \, \text{g/equiv} \times \frac{Q}{96500} \] Substituting the value of \( Q \): \[ W = 31.75 \, \text{g/equiv} \times \frac{24125 \, \text{C}}{96500} \approx 7.5 \, \text{g} \] ### Final Answer The weight of copper displaced by the quantity of electricity that displaces 5600 ml of O₂ at STP is approximately **31.5 grams**. ---

To solve the problem of finding the weight of copper displaced by the quantity of electricity that displaces 5600 ml of O₂ at STP, we can follow these steps: ### Step 1: Calculate the number of moles of O₂ At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22,400 ml. Therefore, the number of moles of O₂ can be calculated using the formula: \[ \text{Number of moles of O}_2 = \frac{\text{Volume of O}_2}{\text{Volume at STP}} = \frac{5600 \, \text{ml}}{22400 \, \text{ml/mol}} = 0.25 \, \text{moles} \] ...
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Knowledge Check

  • The weight of silver (at wt. = 108 ) displaced by a quantity of electricity which displaced 5600 mL of O_(2) at STP will be:

    A
    `5.4 g`
    B
    `10.8 g`
    C
    `54.0 g`
    D
    `108.0 g`
  • The weight of silver (at. Wt.=108) displaced by a quantity of electricity which displaces 5600 mL of O_(2) at STP will be

    A
    5.4 g
    B
    10.8 g
    C
    54.0 g
    D
    108.0 g
  • The weight of silver (at wt. = 108)displaced by a quantity of electricity which displaces 560 mL of O_(2) at STP will be (Volume of 1 mole of gas STP is 22. 4 L)

    A
    54.9 g
    B
    5.4 g
    C
    10.8 g
    D
    108.0g
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