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Hydrogen atom has only one electron, So,...

Hydrogen atom has only one electron, So, mutual repulsion between electrons is absent. However, in multielectron atoms mutual repulsion between the electrons is significant. How does this affect the energy of an electron in the orbitals of the same prinicipal quantum number in multielectron atoms?

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In hydrogen atom, the energy of an electron is determined by the value of n and in multielectron atom, it is determined by n+l . Hence for a given principal quantum. Number electrosn of s,p,d and f-orbtials have different energy (for s,p,d and f,l=01,2 and 3 respectively).
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Hydrogen atom has only one electron, so mutual repulsion between electrons is absent. However, in multielectron atom mutual repulsion between the electrons is significant. How does this affect the energy of an electron in the orbitals of the same principal quantum number in multielectron atoms ?

Hydrogen atom has only one electron, so mutual repulsion between electrons is absent. However, in multielectron atoms mutual repulsion between the electron is absent. However, in multielectron atoms mutual repulsion between the electrons is significant. How does this affect the energy of an electron in the orbitals of the same principal quantum number in multielectron atoms ?

Knowledge Check

  • The total energy of an electron in 4th orbit of hydrogen atom is

    A
    `-13.6eV`
    B
    `-3.4eV`
    C
    `-1.51eV`
    D
    `-0.85eV`

  • Energy of electron in a orbit of H -atom is

    A
    Positive
    B
    Negative
    C
    Zero
    D
    Nothing can be said

  • The energy of an electron in the nth Bohr orbit of hydrogen atom is

    A
    `-(13.6)/(n^(4))`eV
    B
    `-(13.6)/(n^(3))`eV
    C
    `-(13.6)/(n^(2)) ` eV
    D
    `-(13.6)/(n) ` eV

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    Magnetic moment of an electron in nth orbit of hydrogen atom is

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