The average velocity of CO(2) at the tem...

The average velocity of `CO_(2)` at the temperature `T_(1)K` and maximum (most) proable velocity of `CO_(2)` at the temperature `T_(2) K` is `9xx10^(4) cm s^(-1)`. Calculate the values of `T_(1)` and `T_(2)`.

Text Solution

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(i) In gaseous state, `CO_(2)` will exist between the points a and b at temperature `T_(1)`.
(ii) At point b, the plot becomes linear, this show the phase transition, i.e., liquification of `CO_(2)` starts and at point c, it gets completely liquified.
(iii) Similarly, at temperature `T_(2), g` is the point at which `CO_(2)` will be completely liquified.
(iv) Condensation with not take place at `T_(3)` temperature because `T_(3) gt T_(c)` (critical temperature).
(v) Between b and c, liquid and gaseous `CO_(2)` are in equilibrium.

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The average velocity of CO_(2) at T K is 9 xx 10^(4) cm s^(-1) . The value of T is

1682.5K

2143.37

373.20K

1240 K

The rms velocity of CO_(2) at temperature T(in Kelvin) is x cm s^(-1) . At what temperature (in Kelvin) would the rms velocity of nitrous oxide be 4 x cm s^(-1) ?

`16 T`

`2 T`

`4 T`

`32 T`

A perfectly black body emits radiation at temperature T_(1) K. If is to radiate at 16 times this power, its temperature T_(2) K should be

`T_(2)=4T_(1)`

`T_(2)=8T_(1)`

`T_(2)=2T_(1)`

`T_(2)=16T_(1)`