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The decomposition of N(2)O(4) to NO(2) i...

The decomposition of `N_(2)O_(4)` to `NO_(2)` is carried out at `280^(@)C` in chloroform. When equilibrium is reached, `0.2` mol of `N_(2)O_(4)` and `2xx10^(-3)` mol of `NO_(2)` are present in a `2L` solution. The equilibrium constant for the reaction
`N_(2)O_(4) hArr 2NO_(2)` is

A

`1xx 10^(-2)`

B

`2xx10^(-3)`

C

`1xx10^(-5)`

D

`2xx10^(-5)`

Text Solution

Verified by Experts

The correct Answer is:
c
`N_(2)O_(4) hArr 2NO_(2)`,
`[N_(2)O_(4)]=(0.2 "mol")/(2L)=10^(-1) mol^(-1)L`
`[NO_(2)]=(2xx10^(-3)mol)/(2L)=10^(-3)mol^(-1)L`
`K_(p)=(P_(NO_(2))^(2))/(P_(N_(2)O_(4)))=((0.4)^(2))/((1.2)^(2))xx(1.2)/(0.8)=(1)/(6)`
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The decomposition of N_2O_4 into NO_2 is carried out at 280 K in chloroform. When equilibrium has been established, 0.2 mole of N_2O_4 and 2 xx 10^(-3) mole of NO_2 are present in 2 litres of solution. The equilibrium constant for the reaction N_2O_4 Leftrightarrow 2NO_2 is

Knowledge Check

  • The decomposition of N_(2)O_(4) to NO_(2) is carried out at 280^(@)C in chloroform. When equilibrium is reached, 0.2 mol of N_(2)O_(4) and 2xx10^(-3) mol of NO_(2) are present in 2 litre solution. The equilibrium constant for the reaction, N_(2)O_(4)iff2NO_(2) is

    A
    `1xx10^(-3)`
    B
    `2xx10^(-3)`
    C
    `1xx10^(-5)`
    D
    `2xx10^(-5)`

  • The decomposition of N_(2)O_(4) to NO_(2) is carried out at 280 K in chloroform. When equilibrium has been established, 0.2 mole of N_(2)O_(4) and 2xx10^(-3) mole of NO_(2) are present in a 2L solution. The equilibrium constant for the reaction, N_(2)O_(4)hArr2NO_(2) is

    A
    `1xx10^(-2)`
    B
    `2xx10^(-3)`
    C
    `1xx10^(-5)`
    D
    `2xx10^(-5)`

  • The decomposition of N_(2)O_(4) to NO_(2) is carried out at 280K in chloroform. When equilibrium has been estabilished, 0.2 mol of N_(2)O_(4) and 2xx10^(-3) mol of NO_(2) are present in 2 litre solution. The equlibrium constant for reaction N_(2)O_(4)hArr 2NO_(2) is

    A
    `1xx10^(-2)`
    B
    `2xx10^(-3)`
    C
    `1xx10^(-5)`
    D
    `2xx10^(-5)`

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