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HI was heated in a sealed tube at 400^(@...

`HI` was heated in a sealed tube at `400^(@)C` till the equilibrium was reached. HI was found to be `22%` decomposed. The equilibrium constant for dissociation is

A

0.282

B

0.0796

C

0.0199

D

1.99

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(2HI,hArr,H_(2),+,I_(2)),("Eq. conc." 2-(0.22xx2),,0.22,,0.22):}`
`K=((0.22xx0.22))/((1.56)^(2))=.0199`
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Knowledge Check

  • Two moles of HI were heated in a sealed tube at 440^@C till the equilibrium was reached. HI was found to be 22% decomposed. The equilibrium constant for dissociation is

    A
    0.282
    B
    0.0796
    C
    0.0199
    D
    1.99

  • Two moles of HI were heated in a sealed tube at 440^@ C till the equilibrium was reached. HI was found to be 22% decomposed.The equilibrium constant for disssociation is :

    A
    0.282
    B
    0.0796
    C
    0.0199
    D
    1.99

  • HI was heated in a closed tube at 440^(@) C till equilibrium is obtained. At this temperaturee 22% of HI was dossociated. The equilbrium constant for this dissociation wil be

    A
    `0.282`
    B
    `0.0769`
    C
    `0.0199`
    D
    `1.99`

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