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One mole of N(20O(4)(g) at 300K is kept ...

One mole of `N_(20O_(4)(g)` at 300K is kept in a closed container under one atmosphere. It is heated to 600K when 20% of `N_(2)O_(4)(g)` is converted to `NO_(2)(g)`
`N_(2)O_(4)hArr 2NO_(2)(g)` Hence resultant pressure is `:`

A

1.2 atm

B

2.4 atm

C

2.0 atm

D

1.0 atm

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(,N_(2)O_(4),hArr,2NO_(2),),("Initial",1 mol,,,),("Equilibrium",0.8 mol,,0.4 mol,):}`
Total moles at equilibrium
`=0.8 +0.4 =1.2` mol
Pressure due to 1 mol when temperature is doubled `(300-600K) ` is 2 atm.
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