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The perpendicular from the centre of a c...

The perpendicular from the centre of a circle to a chord bisects the chord.

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A perpendicular is drawn from the centre of a circle to the chord
To Find :
To prove that a perpendicular from the centre of a circle to a chord bisects the chord.
Solution :In triangle `OAC` and `OBC`,
`angleOCA = angleOCB` (both angles are` 90^@`)
`OA = OB ` (Radius of the circle)
`OC = OC` (common)
`triangleOAC cong triangleOBC`
`AC = BC` (Congruent parts of congruent triangles are equal)
Thus, C is the midpoint of the chord.
Therefore, the perpendicular drawn from the centre of a circle to a chord bisects the chord.
Hence proved.
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Knowledge Check

  • The radius of a circle is 6 cm. The perpendicular distance from the centre of the circle to the chord which is 8 cm in length is

    A
    `sqrt(5)` cm
    B
    `2 sqrt(5)` cm
    C
    `2 sqrt(7)` cm
    D
    `sqrt(7)` cm
  • A 5 cm long perpendicular is drawn from the centre of a circle to a 24 cm long chord. Find the diameter of the circle.

    A
    A) 26 cm
    B
    B) 32 cm
    C
    C) 13 cm
    D
    D) 30 cm
  • The straight line drawn from the centre of a circle perpendicular to a chord ul("P") the chord. A straight line will not cut a circle in more than ul("O") distinct points. ul("R") chords of a circle are equidistant from the centre of the circle.

    A
    `{:("P","Q","R"),("Trisect","Three","Perpendicular"):}`
    B
    `{:("P","Q","R"),("Defines","Two","Equal"):}`
    C
    `{:("P","Q","R"),("Bisects","Two","Equal"):}`
    D
    `{:("P","Q","R"),("Bisects","Three","Parallel"):}`
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