The rate of change in concentration of `C` in the reaction, `2A+Brarr 2C+3D`, was reported as `1.0` mol `litre^(-1) sec^(-1)`. Calculate the reaction rate as well as rate of change of concentration of A, B and D.

Explanation

We have,
`-(1)/(2) (d[A])/(dt) =(d[B])/(dt)`
`=(1)/(2)(d[C])/(dt)=(1)/(3) (d[D])/(dt)=` rate of reaction
`therefore" "(d[C])/(dt) =1.0" mol litre"^(-1) sec^(-1)`
`therefore" "-(d[A])/(dt) =(d[C])/(dt)=1.0" mol L"^(-1) sec^(-1)`
`-(d[B])/(dt) =(1)/(2) (d[C])/(dt) =(1)/(2) =0.5" mol L"^(-1) sec^(-1)`
`(d[D])/(dt) =(3)/(2) (d[C])/(dt) =(3)/(2)xx1=1.5" mol L"^(-1) sec^(-1)`
Also,
`?" Rate "=(1)/(2) (d[C])/(dt)`
`therefore" Rate "=(1)/(2)xx1=0.5" mol L"^(-1) sec^(-1)`