The yield of alkyl bromide obtained as a result of heating the dry silver salt of carboxyic acid with bromine what will be the order of formation w.r.t. alkyl bromide
The yield of alkyl bromide obtained as a result of heating the dry silver salt of carboxyic acid with bromine what will be the order of formation w.r.t. alkyl bromide
A
`1^(@) gt 3^(@) gt 2^(@)` bromides
B
`1^(@)gt2^(@) gt 3^(@)` bromides
C
`3^(@) gt 2^(@) gt1^(@)` bromides
D
`3^(@) gt 2^(@) gt 1^(@)` bromides
Text Solution
AI Generated Solution
The correct Answer is:
To determine the order of formation of alkyl bromides when heating the dry silver salt of carboxylic acid with bromine, we will analyze the reaction mechanism and the stability of the intermediates involved.
### Step-by-Step Solution:
1. **Understanding the Reaction**:
- The reaction involves the dry silver salt of a carboxylic acid reacting with bromine (Br2).
- This reaction is known as the **Hunsdiecker reaction**, which results in the formation of alkyl bromides (RBr).
2. **Mechanism of the Reaction**:
- The silver salt of the carboxylic acid can be represented as RCOOAg.
- When it reacts with Br2, an acyl hypobromite intermediate is formed:
\[
RCOOAg + Br2 \rightarrow RCOOBr + AgBr
\]
- This intermediate undergoes homolytic cleavage, resulting in the formation of radicals:
\[
RCOOBr \rightarrow R\cdot + Br\cdot + CO2
\]
- The R radical then combines with the Br radical to form the alkyl bromide:
\[
R\cdot + Br\cdot \rightarrow RBr
\]
3. **Stability of Radicals**:
- The stability of the radicals formed during the reaction plays a crucial role in determining the yield of the alkyl bromides.
- The order of stability for alkyl radicals is:
- **Tertiary (3°) > Secondary (2°) > Primary (1°) > Methyl (0°)**
- However, in this reaction, the formation of the alkyl bromide is influenced by the stability of the radical intermediates.
4. **Order of Formation**:
- The yield of alkyl bromides is influenced by the ease of radical formation and the stability of the resulting alkyl radical.
- Due to the nature of the reaction, the order of formation of alkyl bromides is:
- **Primary > Secondary > Tertiary**
- This is because primary radicals are less sterically hindered and can stabilize better compared to secondary and tertiary radicals in this specific reaction context.
5. **Conclusion**:
- Therefore, the order of formation of alkyl bromides when heating the dry silver salt of carboxylic acid with bromine is:
- **Primary > Secondary > Tertiary**
|
Topper's Solved these Questions
ALKYI HALIDE
MOTION|Exercise Exercise - 2 (Level-I) (Prepration of Alkyl halide)|7 VideosView PlaylistALKYI HALIDE
MOTION|Exercise Exercise -2 (Level-II) (Matrix Match)|6 VideosView PlaylistALKYI HALIDE
MOTION|Exercise Exercise - 1 (Chemica l Properties & Preparation methods of Chloroform)|12 VideosView PlaylistALCOHOLS & ETHERS
MOTION|Exercise EXERCISE -4 (LEVEL -II) PREVIOUS YEAR JEE ADVANCED|9 VideosView PlaylistAROMATIC COMPOUND
MOTION|Exercise Exercise - 4 | Level-II|16 VideosView Playlist
Similar Questions
Explore conceptually related problems
Alkyl bromide on treatment with silver fluoride gives alky fluoride. What is this reaction known as ?
Watch solution
Alkanes can be brominated to give the corresponding alkyl bromides by heating with
Watch solution
Knowledge Check
A silver salt of fatty acid on heating with alkyl halide give ,
A silver salt of fatty acid on heating with alkyl halide give ,
A
ether
B
alcohol
C
ester
D
aldehyde
Submit
Similar Questions
Explore conceptually related problems
An alkane C_(8)H_(18) is obtained as the only product on subjecting a primary alkyl halide to Wurtz reaction. On monobromination this alkane yields a single isomer of a tertiary bromide. Write the structure of alkane and the tertiary bromide.
Watch solution
An alkane C_8H_18 is obtained as the only product on subjecting a primary alkyl halide to Wurtz reaction. On monobromination this alkane yields a single isomer of a tertiary bromide . Write the structures of alkane and the tertiary bromide.
Watch solution
Read the given passage and answer questions follow: The hydroxyl group of an alcohol is replaced by halogen on reaction with concentrated halogen acids, phosphorus halides or thionyl chloride. Thionyl chloride is preferred because in this reaction alkyl halide is formed along with gases SO_(2) " and " HCl . The two gaseous products are escapable, hence, the reaction gives pure alkyl halides. The reactions of primary and secondary alcohols with HCl require the presence of a catalyst, ZnCl_(2) . With tertiary alcohols, the reaction is conducted by simply shaking the alcohol with concentrated HCl at room temperature. Constant boiling with HBr (48%) is used for preparing alkyl bromide. Good yields of R- I may be obtained by heating alcohols with sodium or potassium iodide in 95% orthophosphoric acid. The order of reactivity of alcohols with a given haloacid is 3^(@) gt 2^(@) gt 1^(@) . Phosphorus tribromide and triiodide are usually generated in situ (produced in the reaction mixture) by the reaction of red phosphorus with bromine and iodine respectively. Why do we prefer thionyl chloride for the preparation of alkyl halides?
Watch solution
Read the given passage and answer questions follow: The hydroxyl group of an alcohol is replaced by halogen on reaction with concentrated halogen acids, phosphorus halides or thionyl chloride. Thionyl chloride is preferred because in this reaction alkyl halide is formed along with gases SO_(2) " and " HCl . The two gaseous products are escapable, hence, the reaction gives pure alkyl halides. The reactions of primary and secondary alcohols with HCl require the presence of a catalyst, ZnCl_(2) . With tertiary alcohols, the reaction is conducted by simply shaking the alcohol with concentrated HCl at room temperature. Constant boiling with HBr (48%) is used for preparing alkyl bromide. Good yields of R- I may be obtained by heating alcohols with sodium or potassium iodide in 95% orthophosphoric acid. The order of reactivity of alcohols with a given haloacid is 3^(@) gt 2^(@) gt 1^(@) . Phosphorus tribromide and triiodide are usually generated in situ (produced in the reaction mixture) by the reaction of red phosphorus with bromine and iodine respectively. Give the reactivity order of alcohols in halogenation using a haloacid.
Watch solution
Read the given passage and answer questions follow: The hydroxyl group of an alcohol is replaced by halogen on reaction with concentrated halogen acids, phosphorus halides or thionyl chloride. Thionyl chloride is preferred because in this reaction alkyl halide is formed along with gases SO_(2) " and " HCl . The two gaseous products are escapable, hence, the reaction gives pure alkyl halides. The reactions of primary and secondary alcohols with HCl require the presence of a catalyst, ZnCl_(2) . With tertiary alcohols, the reaction is conducted by simply shaking the alcohol with concentrated HCl at room temperature. Constant boiling with HBr (48%) is used for preparing alkyl bromide. Good yields of R- I may be obtained by heating alcohols with sodium or potassium iodide in 95% orthophosphoric acid. The order of reactivity of alcohols with a given haloacid is 3^(@) gt 2^(@) gt 1^(@) . Phosphorus tribromide and triiodide are usually generated in situ (produced in the reaction mixture) by the reaction of red phosphorus with bromine and iodine respectively. Name the reagents that can be used for halogenation of alcohols.
Watch solution
Read the given passage and answer questions follow: The hydroxyl group of an alcohol is replaced by halogen on reaction with concentrated halogen acids, phosphorus halides or thionyl chloride. Thionyl chloride is preferred because in this reaction alkyl halide is formed along with gases SO_(2) " and " HCl . The two gaseous products are escapable, hence, the reaction gives pure alkyl halides. The reactions of primary and secondary alcohols with HCl require the presence of a catalyst, ZnCl_(2) . With tertiary alcohols, the reaction is conducted by simply shaking the alcohol with concentrated HCl at room temperature. Constant boiling with HBr (48%) is used for preparing alkyl bromide. Good yields of R- I may be obtained by heating alcohols with sodium or potassium iodide in 95% orthophosphoric acid. The order of reactivity of alcohols with a given haloacid is 3^(@) gt 2^(@) gt 1^(@) . Phosphorus tribromide and triiodide are usually generated in situ (produced in the reaction mixture) by the reaction of red phosphorus with bromine and iodine respectively. Which catalyst is required when we prepare halogen compounds using concentrated HCI?
Watch solution
Read the given passage and answer questions follow: The hydroxyl group of an alcohol is replaced by halogen on reaction with concentrated halogen acids, phosphorus halides or thionyl chloride. Thionyl chloride is preferred because in this reaction alkyl halide is formed along with gases SO_(2) " and " HCl . The two gaseous products are escapable, hence, the reaction gives pure alkyl halides. The reactions of primary and secondary alcohols with HCl require the presence of a catalyst, ZnCl_(2) . With tertiary alcohols, the reaction is conducted by simply shaking the alcohol with concentrated HCl at room temperature. Constant boiling with HBr (48%) is used for preparing alkyl bromide. Good yields of R- I may be obtained by heating alcohols with sodium or potassium iodide in 95% orthophosphoric acid. The order of reactivity of alcohols with a given haloacid is 3^(@) gt 2^(@) gt 1^(@) . Phosphorus tribromide and triiodide are usually generated in situ (produced in the reaction mixture) by the reaction of red phosphorus with bromine and iodine respectively. How are PBr_(3) " and " PI_(3) prepared for halogenating the hydroxyl group of alcohols ?
Watch solution
MOTION-ALKYI HALIDE-Exercise - 1 (Physical properties and test of Alkyl halide)
- The yield of alkyl bromide obtained as a result of heating the dry sil...
05:41
|
Playing Now - True about alkyl halides is/are -
06:37
|
Play - The correct order of density is -
02:43
|
Play - Ethyl bromide and isopropyl chloride can be distinguished by -
02:30
|
Play - The compound C(2)H(4)Cl(2) has two isomers and they can be distinguish...
Text Solution
|
Play