Home
Class 12
CHEMISTRY
In coparison to a 0.01 M solution of glu...

In coparison to a 0.01 M solution of glucose, the depression in freezing point of a 0.01 M `MgCl_(2)` solution is……

A

the same

B

about twice

C

about three times

D

about six times

Text Solution

AI Generated Solution

The correct Answer is:
To determine the depression in freezing point of a 0.01 M solution of MgCl₂ in comparison to a 0.01 M solution of glucose, we will use the concept of the van 't Hoff factor (i) and the formula for freezing point depression. ### Step-by-Step Solution: 1. **Understand the Freezing Point Depression Formula**: The depression in freezing point (ΔTf) is given by the formula: \[ \Delta T_f = i \cdot K_f \cdot m \] where: - ΔTf = depression in freezing point - i = van 't Hoff factor (number of particles the solute dissociates into) - Kf = freezing point depression constant (depends on the solvent) - m = molality of the solution 2. **Determine the van 't Hoff Factor for Glucose**: Glucose (C₆H₁₂O₆) is a non-electrolyte, meaning it does not dissociate into ions in solution. Therefore, the van 't Hoff factor (i) for glucose is: \[ i_{\text{glucose}} = 1 \] 3. **Determine the van 't Hoff Factor for MgCl₂**: Magnesium chloride (MgCl₂) is an electrolyte and dissociates in water into three ions: \[ \text{MgCl}_2 \rightarrow \text{Mg}^{2+} + 2\text{Cl}^- \] Therefore, the total number of particles (ions) produced is 3. Hence, the van 't Hoff factor for MgCl₂ is: \[ i_{\text{MgCl}_2} = 3 \] 4. **Calculate the Depression in Freezing Point for Each Solution**: Since both solutions have the same molality (0.01 M), we can express the depression in freezing point for both solutions: - For glucose: \[ \Delta T_f^{\text{glucose}} = 1 \cdot K_f \cdot 0.01 \] - For MgCl₂: \[ \Delta T_f^{\text{MgCl}_2} = 3 \cdot K_f \cdot 0.01 \] 5. **Compare the Depression in Freezing Points**: The depression in freezing point for the MgCl₂ solution is three times that of the glucose solution: \[ \Delta T_f^{\text{MgCl}_2} = 3 \cdot \Delta T_f^{\text{glucose}} \] ### Conclusion: The depression in freezing point of a 0.01 M MgCl₂ solution is **3 times** that of a 0.01 M glucose solution.

To determine the depression in freezing point of a 0.01 M solution of MgCl₂ in comparison to a 0.01 M solution of glucose, we will use the concept of the van 't Hoff factor (i) and the formula for freezing point depression. ### Step-by-Step Solution: 1. **Understand the Freezing Point Depression Formula**: The depression in freezing point (ΔTf) is given by the formula: \[ \Delta T_f = i \cdot K_f \cdot m ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOLID STATE

    NCERT EXEMPLAR|Exercise Solid State|77 Videos
  • SURFACE CHEMISTRY

    NCERT EXEMPLAR|Exercise Surface Chemistry|81 Videos

Similar Questions

Explore conceptually related problems

Assertion. 0.1 M solution of glucose has higher increment in the freezing point than 0.1 M solution of urea. Reason. K_(f) for both has different values.

Calculate pH of 0.01 M HCI solution.

Knowledge Check

  • In comparison to a 0.01 M solution of glucose, the depression in freezing point of a 0.01 M MgCl_(2) solution is ………….. .

    A
    the same
    B
    about twice
    C
    about three times
    D
    about six times
  • Read the passage given below and answer the following questions : Raoult's law states that for a solution of volatile liquids, the partial vapour pressure of each component of the solution is directly proportional to its mole fraction present in solution. Dalton's law of partial pressure states that the total pressure P_("total") over the solution phase in the container will be the sum of the partial pressures of the components of the solution and is given as: P_("total") = P_1 + P_2 In comparison to a 0.01 M solution of glucose, the depression in freezing point of a 0.01 M MgCl_2 solution is _ ___

    A
    the same
    B
    about twice
    C
    about three times
    D
    about six times
  • Assertion (A): 0.1 M solution of glucose has same increment in freezing point than has 0.1 M solution of urea. Reason (R ): K_(f) for both has different value.

    A
    If both `(A)` and `(R )` are correct, and `(R )` is the correct explanation of `(A)`.
    B
    If both `(A)` and `(R )` are correct, but `(R )` is not the correct explanation of `(A)`.
    C
    If `(A)` is correct, but `(R )` is incorrect.
    D
    If `(A)` is correct, but `(R )` is correct.
  • Similar Questions

    Explore conceptually related problems

    The boiling point of 0.1 M KCl solution is ………..than 100^(@)C .

    of 0.01 M NaOH solution is

    0.01 M solution each of urea, common salt and sodium sulphate are taken, the ratio of depression in freezing point of these solutions is

    of 0.1 M NaOH solution is

    0.1 M aqueous solution of K_4[Fe(CN)_6] will have the same freezing point as 0.1 M aqueous solution of