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In coparison to a 0.01 M solution of glu...

In coparison to a 0.01 M solution of glucose, the depression in freezing point of a 0.01 M `MgCl_(2)` solution is……

A

the same

B

about twice

C

about three times

D

about six times

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The correct Answer is:
To determine the depression in freezing point of a 0.01 M solution of MgCl₂ in comparison to a 0.01 M solution of glucose, we will use the concept of the van 't Hoff factor (i) and the formula for freezing point depression. ### Step-by-Step Solution: 1. **Understand the Freezing Point Depression Formula**: The depression in freezing point (ΔTf) is given by the formula: \[ \Delta T_f = i \cdot K_f \cdot m \] where: - ΔTf = depression in freezing point - i = van 't Hoff factor (number of particles the solute dissociates into) - Kf = freezing point depression constant (depends on the solvent) - m = molality of the solution 2. **Determine the van 't Hoff Factor for Glucose**: Glucose (C₆H₁₂O₆) is a non-electrolyte, meaning it does not dissociate into ions in solution. Therefore, the van 't Hoff factor (i) for glucose is: \[ i_{\text{glucose}} = 1 \] 3. **Determine the van 't Hoff Factor for MgCl₂**: Magnesium chloride (MgCl₂) is an electrolyte and dissociates in water into three ions: \[ \text{MgCl}_2 \rightarrow \text{Mg}^{2+} + 2\text{Cl}^- \] Therefore, the total number of particles (ions) produced is 3. Hence, the van 't Hoff factor for MgCl₂ is: \[ i_{\text{MgCl}_2} = 3 \] 4. **Calculate the Depression in Freezing Point for Each Solution**: Since both solutions have the same molality (0.01 M), we can express the depression in freezing point for both solutions: - For glucose: \[ \Delta T_f^{\text{glucose}} = 1 \cdot K_f \cdot 0.01 \] - For MgCl₂: \[ \Delta T_f^{\text{MgCl}_2} = 3 \cdot K_f \cdot 0.01 \] 5. **Compare the Depression in Freezing Points**: The depression in freezing point for the MgCl₂ solution is three times that of the glucose solution: \[ \Delta T_f^{\text{MgCl}_2} = 3 \cdot \Delta T_f^{\text{glucose}} \] ### Conclusion: The depression in freezing point of a 0.01 M MgCl₂ solution is **3 times** that of a 0.01 M glucose solution.

To determine the depression in freezing point of a 0.01 M solution of MgCl₂ in comparison to a 0.01 M solution of glucose, we will use the concept of the van 't Hoff factor (i) and the formula for freezing point depression. ### Step-by-Step Solution: 1. **Understand the Freezing Point Depression Formula**: The depression in freezing point (ΔTf) is given by the formula: \[ \Delta T_f = i \cdot K_f \cdot m ...
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