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van't Hoff factor (i) is given by the ex...

van't Hoff factor (i) is given by the expression

A

`i=("normal malar mass")/("abnormal molar mass")`

B

`i=("abnormal molar mass")/("normal molar mass")`

C

`i=("observed colligative property ")/("calculated colligative property ")`

D

`i=("calculated colligative property ")/("observed colligative property")`

Text Solution

Verified by Experts

The correct Answer is:
A, C
van't Hoff factor (i) is a measure of association or dissociation of solute particles which can be calculated as
`i=("normal molar mass")/("abnormal molar mass")`
`=("observed colligative property ")/("calculated colligative property ")`
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Knowledge Check

  • Vant Hoff factor (i)-

    A
    Is less than one in case of dissociation
    B
    Is more than one in case of association
    C
    `i="normal molecular mass"/"observed molecular mass"`
    D
    `i="observed molecular mass"/"normal molecular mass"`

  • The degree of dissociation (alpha) of a weak electrolyte, A_(x)B_(y) is related to van't Hoff's factor (i) by the expression:

    A
    `alpha = (i-1)/((x+y-1))`
    B
    `alpha = (i-1)/((x+y+1))`
    C
    `alpha =((x+y-1))/(i-1)`
    D
    `alpha =((x+y+1))/(i-1)`

  • The degree of dissociation (alpha) of a weak electrolyte A_(x)B_(y) is related to van't Hoff factor (i) by the expression

    A
    `alpha = (i-1)/(x+y+1)`
    B
    `alpha = (x+y-1)/(i-1)`
    C
    `alpha = (x+y+1)/(i-1)`
    D
    `alpha = (i-1)/(x+y-1)`

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