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Rank the following free radicals in orde...

Rank the following free radicals in order of decreasing stability
`(I)C_(6)H_(5) " "overset(.)CHC_(6)H_(5)" "(II)C_(6)H_(5)- overset(.)CH - CH = CH_(2)`
`(III)CH_(3)-overset(.)CH - CH_(3)" "(IV) C_(6)H_(5)- overset(.)CH - CH_(3)`
`(V) CH_(3)CH " "CHCH_(2)overset(.)CH_(2)`
`(VI) CH_(3) - CH_(2) - underset(CH_(3))underset(|)overset(.)C-CH_(3)`

A

`I gt II gt IV gt VI gt III gt V`

B

`VI gt V gt IV gt III gt II gt I`

C

`I gt II gt III gt IV gt V gt VI`

D

`I gt IV gt VI gt V gt II gt III`

Text Solution

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The correct Answer is:
To rank the given free radicals in order of decreasing stability, we will analyze each free radical based on two main factors: resonance and the inductive effect (plus I effect). ### Step-by-Step Solution: 1. **Identify the Free Radicals:** - (I) \( C_6H_5 \cdot CHC_6H_5 \) - (II) \( C_6H_5 \cdot CH - CH = CH_2 \) - (III) \( CH_3 \cdot CH - CH_3 \) - (IV) \( C_6H_5 \cdot CH - CH_3 \) - (V) \( CH_3CH \cdot CHCH_2 \cdot CH_2 \) - (VI) \( CH_3 - CH_2 - (CH_3) \cdot C - CH_3 \) 2. **Analyze Stability Based on Resonance:** - **(I)**: The free radical is stabilized by resonance from two phenyl groups. This makes it highly stable. - **(II)**: The free radical has resonance due to the phenyl group, but only one phenyl group is present, making it less stable than (I). - **(III)**: The free radical has no resonance but is a secondary radical (2°), which is more stable than a primary radical. - **(IV)**: This radical has resonance from the phenyl group and is also a secondary radical, making it more stable than (III). - **(V)**: This is a primary radical (1°) with no resonance, making it less stable than (III) and (IV). - **(VI)**: This is a tertiary radical (3°) with a strong inductive effect from three methyl groups, but no resonance, making it less stable than (I) and (II). 3. **Rank the Free Radicals:** - Based on the analysis, we can rank the radicals in order of decreasing stability: 1. (I) \( C_6H_5 \cdot CHC_6H_5 \) - Most stable due to resonance from two phenyl groups. 2. (II) \( C_6H_5 \cdot CH - CH = CH_2 \) - Stable due to resonance from one phenyl group. 3. (IV) \( C_6H_5 \cdot CH - CH_3 \) - Stable due to resonance and being a secondary radical. 4. (III) \( CH_3 \cdot CH - CH_3 \) - Secondary radical but no resonance. 5. (VI) \( CH_3 - CH_2 - (CH_3) \cdot C - CH_3 \) - Tertiary radical but no resonance, but has a strong inductive effect. 6. (V) \( CH_3CH \cdot CHCH_2 \cdot CH_2 \) - Least stable as it is a primary radical with no resonance. ### Final Ranking: 1. (I) 2. (II) 3. (IV) 4. (III) 5. (VI) 6. (V)
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The stability of given free radicals in decreasing order is (i) CH_(3)-overset(.)(C)H_(2) , (ii) CH_(3)-Coverset(.)(H)-CH_(3) (iii) CH_(3)-underset(CH_(3))underset(|)overset(.)(C)-CH_(3) , (iv) overset(.)(C)H_(3)

Arrange the following carbocations in order of increasing stability : {:(underset("(I)")((CH_(3))_(3)Coverset(+)CH_(2))", "underset("(II)")((CH_(3))_(3)overset(+)C)","),(underset("(III)")(CH_(3)CH_(2)overset(+)CH_(2))", "underset("(IV)")(CH_(3)overset(+)CHCH_(2)CH_(3))):}

Knowledge Check

  • Rank the following free radicals in order of decreasing stability (I) C_(6)H_(5)CH_(6)H_(5) (II) C_(6)H_(5) -CH-CH=CH_(2) (III) CH_(3)-overset(.)CH - CH_(3) (IV) C_(6)H_(5)-overset(.)CH-CH_(3) (V) CH_(3)CH=CHCH_(2)overset(.)CH_(2) (VI) CH_(3)-CH_(2)-underset(CH_(3)) underset(|)overset(.)C-CH_(3)

    A
    `I gt II gt IV gt CI gt HI gt V `
    B
    `VI gt V gt IV gt III gt II gt I`
    C
    `I gt II gt III gt IV gt V gt VI`
    D
    `I gt IV gt VI gt V gt II gt III`
  • Give the stability order of following radicals: (I) CH_(3)-overset(*)(C )H_(2) (II) CH_(3)-overset(*)(C )H-CH_(3) (III) CH_(2)=CH-overset(*)(C )H-CH_(3) (IV)

    A
    `IIIgtIVgtIIgtI`
    B
    `IVgtIIIgtIIgtI`
    C
    `IgtIIgtIIIgtIV`
    D
    `IVgtIIgtIIIgtI`
  • Arrange the following increasing order of number of hyperconjugation structures. (I) CH_(3)-overset(.)(C)H-CH_(3) (II) CH_(3)-overset(CH_(3))overset(|)CH-overset(.)(C)H-CH_(3) (III) CH_(3)-overset(CH_(3))overset(|)underset(.)C-CH_(3)

    A
    `I lt II lt III`
    B
    `II lt I lt III`
    C
    `III lt II lt I`
    D
    `II lt III lt I`
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