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How much volume does one mole of a gas o...

How much volume does one mole of a gas occupy at STP ?

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To find out how much volume one mole of a gas occupies at Standard Temperature and Pressure (STP), we can use the Ideal Gas Law, which is expressed as: \[ PV = nRT \] Where: - \( P \) = Pressure - \( V \) = Volume - \( n \) = Number of moles ...
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Knowledge Check

  • By Avogadro's law, V=kn If volume occupied by 1 mole of a gas at STP is 22.4 L, then what will be the value of k if we take 0.5 mole of gas under same condition of temperature and pressure

    A
    `22.4 L " mol "^(-1)`
    B
    `11.2 L " mol "^(-1)`
    C
    `44.8 L " mol"^(-1)`
    D
    `5.6 L" mol"^(-1)`

  • The vapour denstiy of a gas is 11.2 The volume occupied by one gram of the gas at STP is

    A
    `1.0` L
    B
    `11.2` L
    C
    `22.4` L
    D
    None ot these

  • When pressure is expressed in atmosphere and volume in litres one mole of gas under S.T.P. condition (at 273 K and 1 atmosphere pressure) occupies 22.4 L. Then value of R is-

    A
    `1.0821 "L atm"K^(-1) " mol"^(-1)`
    B
    `0.0821 "L atm"K^(-1) " mol"^(-1)`
    C
    `2.0821 "L atm"K^(-1) " mol"^(-1)`
    D
    None of these

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    Calculate the volume of 1 mole of an ideal gas at STP.

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