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A particle moves in a circle with a unif...

A particle moves in a circle with a uniform speed. When it goes from a point A to a diametrically opposite point B, the momentum of the particle changes by `vecP_(A)-vecP_(B)=2` kg m/s `(hatj)` and the centripetal force acting on it changes by `vecF_(A)-vecF_(B)=8N(hati)` where `hati,hatj` are unit vectors along X and Y axes respectively. The angular velocity of the particle is

A

`"8 rad s"^(-1)`

B

`"4 rad s"^(-1)`

C

`"2 rad s"^(-1)`

D

`"16 rad s"^(-1)`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • A particle of mass M is moving in a horizontal circle of radius R with uniform speed V. When it moves from one point to a diametrically opposite point, its

    A
    Kinetic energy changes by `MV^(2)//4`
    B
    Momentum does not change
    C
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    A
    Kinetic energy changes by `MV^(2)//4`
    B
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    C
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    D
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  • A particle projected from origin moves in x-y plane with a velocity vecv=3hati+6xhatj , where hati" and "hatj are the unit vectors along x and y axis. Find the equation of path followed by the particle :-

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