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A proton is fired from very far away to...

A proton is fired from very far away towards a nucleus with charge Q = 120 e, where e is the electronic charge. It makes a closest approach of `10fm` to the nucleus. The de - Broglie wavelength (in units of fm) of the proton at its start is take the proton mass, `m_p = 5//3xx10^(-27) kg, h//e = 4.2xx10^(-15) J-s//C`, `(1)/(4piepsilon_0) = 9xx10^9m //F, 1 fm = 10^(-15)`.

A

7

B

5

C

9

D

3

Text Solution

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The correct Answer is:
A
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A proton is fired from very for away towards a nucleus with charge Q = 120 e, where e is the electronic charge. It makes a closest approach of 10fm to the nucleus. The de - Broglie wavelength (in units of fm) of the proton at its start is [ take the proton mass, m_p = (5//3xx10^(-27) kg, hle = 4.2xx10^(-15) J-s//C , (1)/(4piepsilon_0) = 9xx10^9m //F, 1 fm = 10^(-15)]

A proton is first from very loward a nucleus with charge Q = 120 e , where e is the nucles The de Brogle wavelength (in unit of fin) of the proton at its start is (tke the proton mass , m _(p) = (5//3) xx 10^(-27) kg h//s = 4.2 xx 10^(-15) J s // C, (1)/(4 pi s_(0)) = 9 xx 10^(9) m//F , 1 fm = 10^(-15) m

Knowledge Check

  • The de broglie wavelength of an electron moving with a speed of 6.6xx10^5 m//s is of the order of (h=6.6xx10^(-34) Js " and " m_e = 9xx10^(-31) kg)

    A
    `10^(-12) m`
    B
    `10^(-11) m`
    C
    `10^(-9) m`
    D
    `10^(-7) m`

  • The de Broglie wavelength of an electron with kinetic energy 120 e V is ("Given h"=6.63xx10^(-34)Js,m_(e)=9xx10^(-31)kg,1e V=1.6xx10^(-19)J)

    A
    `2.13Ã…`
    B
    `1.13Ã…`
    C
    `4.15Ã…`
    D
    `3.14Ã…`

  • Calculate the wavelength (in nanometer) associated with a proton moving at 1.0xx10^(3)ms^(-1) (Mass proton =1.67xx10^(-27)kg and h=6.63xx10^(-34)Js ):-

    A
    `2.5nm`
    B
    `14.0nm`
    C
    `0.032nm`
    D
    `0.40nm`

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    Find the de-Broglie wavelength (in Å) assciated with a photon moving with a velocity 0.5 c, where c=3xx10^(8)m//s , rest mass of proton =1.675xx10^(-27)kg, h=6.6xx10^(-34)Js .

    Find the de Broglie wavelength associated with an electron in a metal at 42^@C of temperature . Take m_e=9.11xx10^(-31)kg .

    The de-Broglie wavelength of an electron is 66 nm. The velocity of the electron is [h= 6.6 xx 10^(-34) kg m^(2)s^(-1), m=9.0 xx 10^(-31) kg]

    Calculate the wavelength in nanometer associated with a proton moving at 1.0xx10^(3)ms^(-1) , (mass of proton = 1.67xx10^(-27)kgandh=6.63xx10^(-34)Js )

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