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When an electron revolves around the nuc...

When an electron revolves around the nucleus, then the ratio of magnetic moment to angular momentum is

A

`e/(2m)`

B

`(2e)/m`

C

`e/m`

D

`(e/m)^2`

Text Solution

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The correct Answer is:
To solve the problem of finding the ratio of magnetic moment to angular momentum for an electron revolving around a nucleus, we will follow these steps: ### Step 1: Define Magnetic Moment The magnetic moment (M) of a current loop is given by the formula: \[ M = I \cdot A \] where \( I \) is the current and \( A \) is the area of the loop. ### Step 2: Calculate the Area For an electron revolving in a circular orbit of radius \( r \), the area \( A \) can be calculated as: \[ A = \pi r^2 \] ### Step 3: Determine the Current The current \( I \) due to the revolving electron can be defined as the charge passing through a point per unit time. The charge of the electron is \( e \). The time \( T \) taken to complete one revolution is the circumference of the circle divided by the velocity \( v \): \[ T = \frac{2\pi r}{v} \] Thus, the current \( I \) is: \[ I = \frac{Q}{T} = \frac{e}{T} = \frac{e \cdot v}{2\pi r} \] ### Step 4: Substitute Current in Magnetic Moment Formula Now we can substitute the expression for current \( I \) into the magnetic moment formula: \[ M = I \cdot A = \left(\frac{e \cdot v}{2\pi r}\right) \cdot (\pi r^2) \] This simplifies to: \[ M = \frac{e \cdot v \cdot r}{2} \] ### Step 5: Define Angular Momentum The angular momentum \( L \) of the electron is given by: \[ L = m \cdot v \cdot r \] where \( m \) is the mass of the electron. ### Step 6: Calculate the Ratio of Magnetic Moment to Angular Momentum Now we can find the ratio of magnetic moment \( M \) to angular momentum \( L \): \[ \text{Ratio} = \frac{M}{L} = \frac{\frac{e \cdot v \cdot r}{2}}{m \cdot v \cdot r} \] Here, \( v \) and \( r \) cancel out: \[ \text{Ratio} = \frac{e}{2m} \] ### Conclusion The ratio of magnetic moment to angular momentum for an electron revolving around a nucleus is: \[ \frac{M}{L} = \frac{e}{2m} \]
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Knowledge Check

  • If an electron of charge (-e) and mass m_(e) revolves around the nucleus of an atom having magnetic moment M_(e) , then angular momentum of electron is

    A
    `L_(0) = (M_(0)e)/(2m_(e))`
    B
    `L_(0) = (e)/(2M_(0)m_(e))`
    C
    `L_(0) = (2M_(0)m_(e))/(e)`
    D
    `L_(0) = (2e)/(M_(0)m_(e))`
  • The ratio of magnetic dipole moment to angular momentum of electron is

    A
    Turns ratio
    B
    Ampere's ratio
    C
    Gyromagnetic ratio
    D
    Poissons ratio
  • The dimensions of ("magnetic moment")/("angular momentum") are

    A
    `[M^(-1)L^(0)TA]`
    B
    `[MLA^(-1)T^(-1)]`
    C
    `[M^(3)LT^(-2)A^(-1)]`
    D
    `[ML^(-1)T^(2)A^(-1)]`
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