In which of following compound a `ppi - dpi` bonding is present

Options

A. Trisilylamine
B. Graphite
C. Dimethyl amine
D. Diamond

Answer

To determine which compound contains P-Pi-D-Pi bonding, we need to analyze the bonding characteristics of each compound listed in the question.

### Step-by-Step Solution:

1. **Understanding P-Pi-D-Pi Bonding**:
- P-Pi-D-Pi bonding involves the overlap of p-orbitals from one atom with d-orbitals from another atom. This type of bonding typically occurs in compounds where transition metals (which have d-orbitals) interact with elements that can form pi bonds.

2. **Analyzing Each Compound**:
- **Trisilylamine (Si3N)**
- This compound contains silicon and nitrogen. Silicon is in the third period and does not have d-orbitals that can participate in P-Pi-D-Pi bonding. Therefore, it does not exhibit this type of bonding.

- **Graphite (C)**
- Graphite is an allotrope of carbon composed entirely of carbon atoms. Carbon is in the second period and lacks d-orbitals. Thus, graphite cannot exhibit P-Pi-D-Pi bonding.

- **Dimethylamine (C2H7N)**
- Dimethylamine consists of carbon, hydrogen, and nitrogen. While nitrogen can form pi bonds, it does not have d-orbitals available for bonding. Therefore, dimethylamine does not exhibit P-Pi-D-Pi bonding.

- **Diamond (C)**
- Diamond is another allotrope of carbon, consisting solely of carbon atoms arranged in a tetrahedral structure. Like graphite, diamond is composed of carbon, which has no d-orbitals. Thus, it cannot exhibit P-Pi-D-Pi bonding.

3. **Conclusion**:
- After analyzing all the compounds, none of them exhibit P-Pi-D-Pi bonding. Therefore, the answer is that **none of the given compounds contain P-Pi-D-Pi bonding**.