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A diameter of a circle is a chord that……...

A diameter of a circle is a chord that………the centre.

A

is away from

B

do not pass through

C

passes through

D

None of the above

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question "A diameter of a circle is a chord that………the centre," we need to fill in the blank with the appropriate term. Let's go through the steps to arrive at the answer. ### Step-by-Step Solution: 1. **Understanding the Definitions**: - A **circle** is defined as the set of all points that are equidistant from a fixed point called the **center**. - A **diameter** is a special type of chord that passes through the center of the circle. - A **chord** is any line segment with both endpoints on the circle. 2. **Identifying the Relationship**: - Since a diameter is a type of chord, we need to understand that not all chords pass through the center. However, the diameter specifically does. 3. **Filling in the Blank**: - The statement is: "A diameter of a circle is a chord that ______ the center." - Since we know that a diameter must go through the center of the circle, we can fill in the blank with the word "passes through". 4. **Final Answer**: - Therefore, the complete statement is: "A diameter of a circle is a chord that **passes through** the center."
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Prove that a diameter of a circle which bisects a chord of the circle also bisects the angle subtended by the chord at the centre of the circle.

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Knowledge Check

  • O is the centre of a circle. AB is a chord of the circle but not its diameter. OC is perpendicular to AB. If OC = CB and radius of the circle be 7 cm, then the length of AB is

    A
    `7 sqrt(2) cm`
    B
    `14 cm`
    C
    7 cm
    D
    `(7)/( sqrt(2))` cm
  • In a circle with the centre is O and AB is the diameter of the circle and CD is the chord of the circle. If angle ABC is 54^@ and the length of CD and BC is equal, then find the angle DBC.

    A
    1. `36^@`
    B
    2. `24^@`
    C
    3. `48^@`
    D
    4. `12^@`
  • In a circle with centre O, AOC is a diameter of the circle, BD is a chord and OB and CD are joined. If angle AOB = 130^@ , then angle BDC is equal to

    A
    `30^@`
    B
    `25^@`
    C
    `50^@`
    D
    `60^@`
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    Prove that, if a diameter of a circle bisects two chords of the circle then those two chords are parallel to each other.

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