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Find the modulus and argument of the com...

Find the modulus and argument of the complex number `(1+2i)/(1-3i)`.

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To find the modulus and argument of the complex number \(\frac{1+2i}{1-3i}\), we will follow these steps: ### Step 1: Simplify the Complex Number We need to simplify the complex number by multiplying the numerator and the denominator by the conjugate of the denominator. \[ \text{Conjugate of } (1 - 3i) = 1 + 3i \] Now, we multiply both the numerator and the denominator by \(1 + 3i\): \[ \frac{1 + 2i}{1 - 3i} \cdot \frac{1 + 3i}{1 + 3i} = \frac{(1 + 2i)(1 + 3i)}{(1 - 3i)(1 + 3i)} \] ### Step 2: Calculate the Denominator Using the formula \(a^2 - b^2\) for the denominator: \[ (1 - 3i)(1 + 3i) = 1^2 - (3i)^2 = 1 - 9(-1) = 1 + 9 = 10 \] ### Step 3: Calculate the Numerator Now, we expand the numerator: \[ (1 + 2i)(1 + 3i) = 1 \cdot 1 + 1 \cdot 3i + 2i \cdot 1 + 2i \cdot 3i = 1 + 3i + 2i + 6i^2 \] Since \(i^2 = -1\): \[ = 1 + 5i - 6 = -5 + 5i \] ### Step 4: Combine the Results Now we can combine the results from the numerator and denominator: \[ \frac{-5 + 5i}{10} = -\frac{1}{2} + \frac{1}{2}i \] ### Step 5: Find the Modulus The modulus of a complex number \(z = a + bi\) is given by: \[ |z| = \sqrt{a^2 + b^2} \] Here, \(a = -\frac{1}{2}\) and \(b = \frac{1}{2}\): \[ |z| = \sqrt{\left(-\frac{1}{2}\right)^2 + \left(\frac{1}{2}\right)^2} = \sqrt{\frac{1}{4} + \frac{1}{4}} = \sqrt{\frac{2}{4}} = \sqrt{\frac{1}{2}} = \frac{1}{\sqrt{2}} \] ### Step 6: Find the Argument The argument \(\theta\) of a complex number is given by: \[ \tan(\theta) = \frac{b}{a} \] In our case: \[ \tan(\theta) = \frac{\frac{1}{2}}{-\frac{1}{2}} = -1 \] The angle whose tangent is \(-1\) is \(-\frac{\pi}{4}\). However, since the real part is negative and the imaginary part is positive, the complex number lies in the second quadrant. Therefore, we adjust the angle: \[ \theta = \pi - \frac{\pi}{4} = \frac{3\pi}{4} \] ### Final Answer Thus, the modulus and argument of the complex number \(\frac{1+2i}{1-3i}\) are: - Modulus: \(\frac{1}{\sqrt{2}}\) - Argument: \(\frac{3\pi}{4}\)

To find the modulus and argument of the complex number \(\frac{1+2i}{1-3i}\), we will follow these steps: ### Step 1: Simplify the Complex Number We need to simplify the complex number by multiplying the numerator and the denominator by the conjugate of the denominator. \[ \text{Conjugate of } (1 - 3i) = 1 + 3i \] ...
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NCERT-COMPLEX NUMBERS AND QUADRATIC EQUATIONS-MISCELLANEOUS EXERCISE
  1. If x + i y =sqrt((a+i b)/(c+i d)) prove that (x^2+y^2)^2=(a^2+b^2)/(c^...

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  2. Find the number of non-zero integral solutions of the equation |1-i|^...

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  3. If (a + i b) (c + i d) (e + if) (g + i h) = A + i B, then show that (a...

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  4. Let z1=2-i ,z2=-2+i. Find Re ((z1z2)/( bar z'1))

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  5. Find the modulus and argument of the complex number (1+2i)/(1-3i).

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  6. If z1=2-i ,z2=1+i ,find |(z1+z2+1)/(z1-z2+i)|

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  7. If a + i b =((x+i)^2)/(2x^2+1),prove that a^2+b^2=((x^2+1)^2)/((2x^2+...

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  8. If alphaand betaare different complex numbers with |beta|=1,then fin...

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  9. Find the real numbers x and y if (x-i y)(3+5i) is the conjugate of -6...

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  10. Find the modulus of (1+i)/(1-i)-(1-i)/(1+i).

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  11. If (x+i y)^3=u+i v ,then Find p if u/x+v/y=p(x^2-y^2).

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  12. Convert the following in the polar form : (i) (1+7i)/((2-i)^2) (ii) ...

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  13. Solve the equation :x^2-2x+3/2=0

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  14. Solve the equation : 3x^2-4x+(20)/3=0

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  15. Evaluate : [i^(18)+(1/i)^(25)]^3

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  16. Reduce (1/(1-4i)-2/(1+i))((3-4i)/(5+i))to the standard form.

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  17. For any two complex numbers z1and z2, prove that Re(z1z2)=Re(z1) Re(z2...

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  18. Solve the equation :21 x^2-28 x+10=0

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  19. Solve the equation :27 x^2-10 x+1=0

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  20. If ((1+i)/(1-i))^m=1,then find the least integral value of m.

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