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Find the modulus and argument of the com...

Find the modulus and argument of the complex number `(1+2i)/(1-3i)`.

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To find the modulus and argument of the complex number \(\frac{1+2i}{1-3i}\), we will follow these steps: ### Step 1: Simplify the Complex Number We need to simplify the complex number by multiplying the numerator and the denominator by the conjugate of the denominator. \[ \text{Conjugate of } (1 - 3i) = 1 + 3i \] Now, we multiply both the numerator and the denominator by \(1 + 3i\): \[ \frac{1 + 2i}{1 - 3i} \cdot \frac{1 + 3i}{1 + 3i} = \frac{(1 + 2i)(1 + 3i)}{(1 - 3i)(1 + 3i)} \] ### Step 2: Calculate the Denominator Using the formula \(a^2 - b^2\) for the denominator: \[ (1 - 3i)(1 + 3i) = 1^2 - (3i)^2 = 1 - 9(-1) = 1 + 9 = 10 \] ### Step 3: Calculate the Numerator Now, we expand the numerator: \[ (1 + 2i)(1 + 3i) = 1 \cdot 1 + 1 \cdot 3i + 2i \cdot 1 + 2i \cdot 3i = 1 + 3i + 2i + 6i^2 \] Since \(i^2 = -1\): \[ = 1 + 5i - 6 = -5 + 5i \] ### Step 4: Combine the Results Now we can combine the results from the numerator and denominator: \[ \frac{-5 + 5i}{10} = -\frac{1}{2} + \frac{1}{2}i \] ### Step 5: Find the Modulus The modulus of a complex number \(z = a + bi\) is given by: \[ |z| = \sqrt{a^2 + b^2} \] Here, \(a = -\frac{1}{2}\) and \(b = \frac{1}{2}\): \[ |z| = \sqrt{\left(-\frac{1}{2}\right)^2 + \left(\frac{1}{2}\right)^2} = \sqrt{\frac{1}{4} + \frac{1}{4}} = \sqrt{\frac{2}{4}} = \sqrt{\frac{1}{2}} = \frac{1}{\sqrt{2}} \] ### Step 6: Find the Argument The argument \(\theta\) of a complex number is given by: \[ \tan(\theta) = \frac{b}{a} \] In our case: \[ \tan(\theta) = \frac{\frac{1}{2}}{-\frac{1}{2}} = -1 \] The angle whose tangent is \(-1\) is \(-\frac{\pi}{4}\). However, since the real part is negative and the imaginary part is positive, the complex number lies in the second quadrant. Therefore, we adjust the angle: \[ \theta = \pi - \frac{\pi}{4} = \frac{3\pi}{4} \] ### Final Answer Thus, the modulus and argument of the complex number \(\frac{1+2i}{1-3i}\) are: - Modulus: \(\frac{1}{\sqrt{2}}\) - Argument: \(\frac{3\pi}{4}\)

To find the modulus and argument of the complex number \(\frac{1+2i}{1-3i}\), we will follow these steps: ### Step 1: Simplify the Complex Number We need to simplify the complex number by multiplying the numerator and the denominator by the conjugate of the denominator. \[ \text{Conjugate of } (1 - 3i) = 1 + 3i \] ...
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Knowledge Check

  • The modulus and principle argument of the complex number (1+2i)/(1-(1-i)^(2) are respectively

    A
    `1,0`
    B
    `1,1`
    C
    `2,0`
    D
    `2,1`
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