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The percentage change in the pressure of...

The percentage change in the pressure of a given mass of a gas at constant temperature is 50% (increases). Calculate the percentage in the pressure of the gas.

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To solve the problem, we need to determine the percentage change in the volume of a gas when the pressure increases by 50% at constant temperature. We'll use Boyle's Law, which states that for a given mass of gas at constant temperature, the product of pressure and volume is constant (P1V1 = P2V2). ### Step-by-Step Solution: 1. **Understand the Given Information**: - Initial pressure (P1) and final pressure (P2) are related by a 50% increase in pressure. - This means P2 = P1 + 0.5P1 = 1.5P1. 2. **Apply Boyle's Law**: - According to Boyle's Law: P1V1 = P2V2. - Rearranging gives us V2 = (P1/P2) * V1. 3. **Substitute P2**: - We know P2 = 1.5P1, so we can substitute this into the equation for V2: \[ V2 = \left(\frac{P1}{1.5P1}\right) * V1 = \frac{1}{1.5} * V1 = \frac{2}{3} V1. \] 4. **Calculate the Change in Volume**: - The change in volume (ΔV) is given by: \[ ΔV = V2 - V1 = \frac{2}{3}V1 - V1 = \frac{2}{3}V1 - \frac{3}{3}V1 = -\frac{1}{3}V1. \] 5. **Calculate the Percentage Change in Volume**: - The percentage change in volume is calculated as: \[ \text{Percentage Change} = \left(\frac{ΔV}{V1}\right) * 100 = \left(-\frac{1/3 V1}{V1}\right) * 100 = -\frac{1}{3} * 100 = -33.33\%. \] ### Final Result: The volume of the gas decreases by 33.33%.
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