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A metal M of equivalent mass E forms an ...

A metal `M` of equivalent mass `E` forms an oxide of molecular formula `M_(x)O_(y)` The atomic mass of the metal is given by the correct equation .

A

`(2En)/(m)`

B

2mEn

C

`(E )/(n)`

D

`(ME)/(2n)`

Text Solution

Verified by Experts

The correct Answer is:
A
Amount of X that combines with 8 g of oxygen,
i.e., `E=(m xx"Atomic mass")/(n xx2)`
`therefore " Atomic mass"=(2En)/(m)`
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Knowledge Check

  • A metal M of equivalent mass E forms an oxide of molecular formula M_x O_3 The atomic mass of the metal is given by the correct equation

    A
    `2E(y//x)`
    B
    `xy//E`
    C
    `E//y`
    D
    `y//E`

  • A metal M of equivalent man E forms an oxide of molecular formula MxOy. The atomic mass of the metal is given by the correct equation.

    A
    2E `(y//x)`
    B
    xyE
    C
    `E//Y`
    D
    `Y//E`

  • The percentage of element M is 53 in its oxide of molecular formula M_(2)O_(3) . Its atomic mass is about

    A
    `45`
    B
    `9`
    C
    `18`
    D
    `36`

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