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One litre sample of water contains 0.9 ...

One litre sample of water contains 0.9 mg `CaCl_(2)` and 0.9 mg of `MgCl_(2)`. Find the total hardness in terms of parts permillion of `CaCO_(3)`.

Text Solution

Verified by Experts

`111 g CaCl_(2)-=100 g CaCO_(3)`
`therefore " " 0.9 mg CaCl_(2) -=(100)/(111)xx0.9 mg CaCO_(3)`
`-=0.81 mg " of" CaCO_(3)`
` 95 g MgCl -=100 g CaCO_(3)`
` therefore " " 0.9 mg MgCl_(2) -=(100)/(95)xx0.9 mg CaCO_(3)`
`-=0.94 mg " of " CaCO_(3)`
Thus, 1 litre water to `10^(6)`. mg water contains (0.81+0.94 = 1.75 mg) i.e., hardness of water is 1.75 ppm.
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Knowledge Check

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