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At infinite dilution, the equivalent con...

At infinite dilution, the equivalent conductivity of the electrolyte is given by the expression:
`^^^_(eq)^(oo)=lambda_((+))^(oo)+lambda_((-))^(oo)`
The above expression is given by

A

Kohlrausch

B

Hittoff

C

Ostwald

D

De-bye Huckel.

Text Solution

Verified by Experts

The correct Answer is:
A
This is as per statement of Kohlrausc h's law.
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Knowledge Check

  • The equivalent conductance (Lambda_(eq.)) is given by the relation

    A
    `Lambda_(eq.) = 1000(kappa)/(N)`
    B
    `Lambda_(eq.) = 1000(N)/(kappa)`
    C
    `Lambda_(eq.) = 1000kappa//N`
    D
    `Lambda_(eq.) = 1000(kappa)/(N)^(2)`

  • The unit of equivalent conductivity (Lambda_(eq.)) are

    A
    `ohm^(-1)cm^(2)eq^(-1)`
    B
    `ohm^(-2)cm^(2)`
    C
    `ohm^(-1)cm^(-1)`
    D
    `ohm^(-1)cm^(-2)`

  • The equivalent conductance of NaCl at concentration C and at infinite dilution are lamda_(C) and lamda_(oo) , respectively. The correct (where the constant B is positive)

    A
    `lamda_(C)=lamda_(oo)+(B)C`
    B
    `lamda_(C)=lamda_(oo)-(B)C`
    C
    `lamda_(C)=lamda_(oo)-(B)sqrt(C)`
    D
    `lamda_(C)=lamda_(oo)+(B)sqrt(C)`

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    The equivalent conductance of NaCl at concentration of C and at infinite dilution are lambda_(C) and lambda_(oo) respectively. The correct relationship between lambda_(C) and lambda_(oo) is given as : ( where the constant B is positive )

    The equivalent conductance of NaCI at concentration C and at infinited dilution are lambda_c and lambda_(infinity) is given as.

    Conductors allow the passage of electric current through them. Metallic and electrolytic are the two type of conductors. Current carriers in metallic and electrolytic conductors are free electrons and free ions respectively. Specific conductance or consuctivity of the electrolyte solution is given by the following relation : kappa=c xx l/A where, c=1//R is the conductance and l//A is the cell constant. Molar conductance (Lambda_(m)) and equivalence conductance (Lambda_(e)) of an electrolyte solution are calculated using the following similar relations : Lambda_(m)= kappa xx 1000/M Lambda_(e)= kappa xx 1000/N Where, M and N are the molarity and normality of the solution respectively. Molar conductance of strong electrolyte depends on concentration : Lambda_(m)=Lambda_(m)^(@)-b sqrt(c) where, Lambda_(m)^(@)= molar conductance at infinite dilution c= concentration of the solution b= constant The degrees of dissociation of weak electrolytes are calculated as : alpha=Lambda_(m)/Lambda_(m)^(@)=Lambda_(e)/Lambda_(e)^(@) The correct order of equivalent conductances at infinite dilution of LiCl, NaCl and KCl is :

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