In Which case (s), there is change in ox...

In Which case (s), there is change in oxidation number ?

Aqueous solution of `CrO_(4)^(2-)` is acidified

`SO_(2)` gas is passed through acidified `Cr_(2)O_(7)^(2-)` solution

`Cr_(2)O_(7)^(2-)` solution is made alkaline

`CrO_(2)Cl_(2)` is is dissolved in NaOH.

Text Solution

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The correct Answer is:

(a) `2overset(+6)(Cr)O_(4)^(2-)+2H^(+)rarroverset(+6)Cr_(2)O_(7)^(2-)+H_(2)O " "("no change")`
`overset(+6)Cr_(2)O_(4)^(2-)+3overset(+4)SO_(2)+2H^(+)rarr2overset(+3)Cr^(3+)+3overset(+6)SO_(4)^(2-)+H_(2)O" "("change")`
`overset(+6)Cr_(2)O_(7)^(2-)+2OH^(-)rarr2overset(+6)CrO_(4)^(2-)+H_(2)O" "("no change")`
`overset(+6)CrO_(2)Cl_(2)+2NaOHrarrNaoverset(+6)CrO_(4)+2HCl" "("no change")`.

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In which reaction, there is change in oxidation number of N atom?

`2NO_(2) iff N_(2)O_(4)`

`2NO_(2)+H_(2)O rarr HNO_(3)+HNO_(2)`

`NH_(4)OH rarr NH_(4)^(+)+OH^(-)`

`N_(2)O_(5)+H_(2)O rarr 2HNO_(3)`

Identify the cases(s) where there in change in oxidation number.

Acidified soltuion of `Cr_(2)O_(4)^(2-)`

`SO_(2)` gas bubbled throught an acidic solution of `Cr_(2)O_(7)^(2-)`

Alkaline solution of `Cr_(2)O_(7)^(2-)`

Ammoniacal solution of `CrO_(4)^(2-)`

Identify the case where there is change in oxidation number

Acidified solution of `CrO_(4)^(2-)`

`SO_(2)` gas bubbled through an acidic solution of `Cr_(2)O_(7)^(2-)`

alkaline solution of `CrO_(4)^(2-)`

aqueous solution of `CrO_(2)CI_(2)` in NaOH