A solution `M` is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is `0.9`
Given: Freezing point depression constant of water
`(K_(f)^(water)=1.86 K kg mol^(-1))`
Freezing point depression constant to ethanol
`(K_(f)^(ethanol))=2.0 K kg mol^(-1))`
Boiling point elevation constant of water
`(K_(b)^(water))=0.52 K kg mol^(-1))`
Boiling point elevation constant of ethanol
`(K_(b)^(ethanol))=1.2 K kg mol^(-1))`
Standard freezing point of water = `273 K `
Standard freezing point of ethanol = `155.7 K `
Standard boiling point of water = `373 K `
Standard boiling point of ethanol = `351.5 K `
Vapour pressure of pure water =`32.8 mm Hg`
Vapour pressure of pure ethanol =`40 mm Hg`
Molecular weight of water =`18 g mol^(-1)`
Molecular weight of ethanol =`46 g mol^(-1)`
In anwering the following questions consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative.
The freezing point of the solution `M` is
A solution `M` is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is `0.9`
Given: Freezing point depression constant of water
`(K_(f)^(water)=1.86 K kg mol^(-1))`
Freezing point depression constant to ethanol
`(K_(f)^(ethanol))=2.0 K kg mol^(-1))`
Boiling point elevation constant of water
`(K_(b)^(water))=0.52 K kg mol^(-1))`
Boiling point elevation constant of ethanol
`(K_(b)^(ethanol))=1.2 K kg mol^(-1))`
Standard freezing point of water = `273 K `
Standard freezing point of ethanol = `155.7 K `
Standard boiling point of water = `373 K `
Standard boiling point of ethanol = `351.5 K `
Vapour pressure of pure water =`32.8 mm Hg`
Vapour pressure of pure ethanol =`40 mm Hg`
Molecular weight of water =`18 g mol^(-1)`
Molecular weight of ethanol =`46 g mol^(-1)`
In anwering the following questions consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative.
The freezing point of the solution `M` is
Given: Freezing point depression constant of water
`(K_(f)^(water)=1.86 K kg mol^(-1))`
Freezing point depression constant to ethanol
`(K_(f)^(ethanol))=2.0 K kg mol^(-1))`
Boiling point elevation constant of water
`(K_(b)^(water))=0.52 K kg mol^(-1))`
Boiling point elevation constant of ethanol
`(K_(b)^(ethanol))=1.2 K kg mol^(-1))`
Standard freezing point of water = `273 K `
Standard freezing point of ethanol = `155.7 K `
Standard boiling point of water = `373 K `
Standard boiling point of ethanol = `351.5 K `
Vapour pressure of pure water =`32.8 mm Hg`
Vapour pressure of pure ethanol =`40 mm Hg`
Molecular weight of water =`18 g mol^(-1)`
Molecular weight of ethanol =`46 g mol^(-1)`
In anwering the following questions consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative.
The freezing point of the solution `M` is
A
`268.7 K`
B
`268.5 K`
C
`234.2 K`
D
`150.9 K`
Text Solution
Verified by Experts
The correct Answer is:
D
Solution M is mixture of ethanol and water, Mole fraction of ethanol is 0.9 (Solvent is `C_(2)H_(5)OH`) Mole fraction water is 0.1 (`H_(2)O` is solute)
Molality of `H_(2)O=(n_(2)xx1000)/(n_(1)M_(1))`
`=(0.1xx1000)/(0.9xx46)=2.415` m
`DeltaT_(f)=K_(f)m=2xx2.2415=4.83`
Freezing point of solution
`= 155.7 - 4.83 = 150.87 K`
Total vapour pressure, `p=p_(A)^(@)xx A`.
Molality of `H_(2)O=(n_(2)xx1000)/(n_(1)M_(1))`
`=(0.1xx1000)/(0.9xx46)=2.415` m
`DeltaT_(f)=K_(f)m=2xx2.2415=4.83`
Freezing point of solution
`= 155.7 - 4.83 = 150.87 K`
Total vapour pressure, `p=p_(A)^(@)xx A`.
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A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9 Given: Freezing point depression constant of water (K_(f)^(water)=1.86 K kg mol^(-1)) Freezing point depression constant to ethanol (K_(f)^(ethanol))=2.0 K kg mol^(-1)) Boiling point elevation constant of water (K_(b)^(water))=0.52 K kg mol^(-1)) Boiling point elevation constant of ethanol (K_(b)^(ethanol))=1.2 K kg mol^(-1)) Standard freezing point of water = 273 K Standard freezing point of ethanol = 155.7 K Standard boiling point of water = 373 K Standard boiling point of ethanol = 351.5 K Vapour pressure of pure water = 32.8 mm Hg Vapour pressure of pure ethanol = 40 mm Hg Molecular weight of water = 18 g mol^(-1) Molecular weight of ethanol = 46 g mol^(-1) In anwering the following questions consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative. The vapour pressure of the solution M is
Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties. Applications of colligative properties are very useful in day-to-day life. one of its examples is the use of ethylene glycol adn water mixtures as anti-freezing liquid in the radiator of automobiles. A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9 . Given: Freezing point depression constant of water (K_(f)^(water)) = 1.86 K kg mol^(-1) Freezing point depression constant of ethanol (K_(f)^("ethanol")) = 2.0 K kg mol^(-1) Boiling point elevation constant of water (K_(b)^(water)) = 0.52 K kg mol^(-1) Boiling point elevation constant of ethanol (K_(b)^("ethanol")) = 1.2 K kg mol^(-1) Standard freezing point of water = 273 K Standard freezing point of ethanol = 155.7 K Standard boiling point of water = 373 K Standard boiling point of ethanol = 351.5 K Vapour pressure of pure water = 32.8 mm Hg Vapour pressure of pure ethanol = 40 mm Hg Molecular weight of water =18 g mol^(-1) Molecular weight of ethanol = 46 g mol^(-1) In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative. The vapour pressure of the solution M is
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Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties. Applications of colligative properties are very useful in day-to-day life. One of its examples is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator of automobiles. A solution M is prepared by mixing ethanol and water. Thus moel fraction of ethanol in the mixture is 0.9 . Given: Freezing point depression constant of water (K_(f)^("water")) = 1.86 K kg mol^(-1) Freezing point depression constant of ethanol (K_(f)^("ethanol")) = 2.0 K kg mol^(-1) Boiling point elevation constant of water (K_(b)^("water")) = 0.52 K kg mol^(-1) Boiling point elevation constant of ethanol (K_(b)^("ethanol")) = 1.2 K kg mol^(-1) Standard freezing point of water = 273 K Standard freezing point of ethanol = 155.7K Standard boiling point of water = 373 K Standard boiling point of ethanol = 351.5 K vapour pressure of pure water = 32.8 mm Hg Vapour pressure of pure ethanol = 40 mm Hg Molecualr weight of water = 18 g mol^(-1) Molecular weight of ethanol = 46 g mol^(-1) In asweering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative. The freezing point of the solution M is :
Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties. Applications of colligative properties are very useful in day-to-day life. One of its examples is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator of automobiles. A solution M is prepared by mixing ethanol and water. Thus moel fraction of ethanol in the mixture is 0.9 . Given: Freezing point depression constant of water (K_(f)^("water")) = 1.86 K kg mol^(-1) Freezing point depression constant of ethanol (K_(f)^("ethanol")) = 2.0 K kg mol^(-1) Boiling point elevation constant of water (K_(b)^("water")) = 0.52 K kg mol^(-1) Boiling point elevation constant of ethanol (K_(b)^("ethanol")) = 1.2 K kg mol^(-1) Standard freezing point of water = 273 K Standard freezing point of ethanol = 155.7K Standard boiling point of water = 373 K Standard boiling point of ethanol = 351.5 K vapour pressure of pure water = 32.8 mm Hg Vapour pressure of pure ethanol = 40 mm Hg Molecualr weight of water = 18 g mol^(-1) Molecular weight of ethanol = 46 g mol^(-1) In asweering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative. The freezing point of the solution M is :
A
`268.7K`
B
`268.5K`
C
`234.2K`
D
`150.9K`
Some properties as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties. Applications of colligative properties are useful in day-to day life. Its example is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator of automobiles. A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9. Given : Freezing point depression constant of water (K_(f)^("water"))=1.86" K kg mol"^(-1) Freezing point depression constant of ethanol (K_(f)^("ethanol"))=2.0"K kg mol"^(-1) Boiling point elevation of water (K_(b)^("water"))=0.52" K kg mol"^(-1) Boiling point elevation constant of ethanol (K_(b)^("ethanol"))=1.2" K kg mol"^(-1) Standard freezing point of water = 273 K Standard freezing point of ethanol = 155.7 K Standard boiling point of water = 373 K Standard boiling point of ethanol = 251.5 K Vapour pressure of pure water = 32.8 mm Hg Vapour pressure of pure ethanol = 40 mm Hg Molecular weight of water = 18 g mol^(-1) Molecular weight of ethanol = 46 g mol^(-1) In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative. The freezing point of the solution M is
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A
268.7 K
B
268.5 K
C
234.2 K
D
150.9 K
Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties. Application of colligative properties are very useful in day- to - day life. One of its examples is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator of automobiles. A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9. Given : Freezing point depression constant of water (K_(f)^("water"))="1.86 K kg mol"^(-1) Freezing point depression constant of ethanol (e_(f)^("ethanol"))="2.0 K kg mol"^(-1) Boiling point elevation constant of water (K_(b)^("water"))="0.52 K kg mol"^(-1) Boiling point elevation constant of ethanol (K_(b)^("ethanol"))="1.2 K kg mol"^(-1) Standard freezing point of water = 273 K Standard freezing point of ethanol = 155.7 K Standard boiling point of water = 373 K Standard boiling point of ethanol = 351.5 K Vapour pressure of pure water = 32.8 mm Hg Vapour pressusre of pure ethanol = 40 mm Hg Molecular weight of water = "18 g mol"^(-1) Molecular weight of ethanol = "46 g mol"^(-1) In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative. The freezing point of solution M is
Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties. Application of colligative properties are very useful in day- to - day life. One of its examples is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator of automobiles. A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9. Given : Freezing point depression constant of water (K_(f)^("water"))="1.86 K kg mol"^(-1) Freezing point depression constant of ethanol (e_(f)^("ethanol"))="2.0 K kg mol"^(-1) Boiling point elevation constant of water (K_(b)^("water"))="0.52 K kg mol"^(-1) Boiling point elevation constant of ethanol (K_(b)^("ethanol"))="1.2 K kg mol"^(-1) Standard freezing point of water = 273 K Standard freezing point of ethanol = 155.7 K Standard boiling point of water = 373 K Standard boiling point of ethanol = 351.5 K Vapour pressure of pure water = 32.8 mm Hg Vapour pressusre of pure ethanol = 40 mm Hg Molecular weight of water = "18 g mol"^(-1) Molecular weight of ethanol = "46 g mol"^(-1) In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative. The freezing point of solution M is
A
268.7 K
B
268.5 K
C
234.2 K
D
150.9 K
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Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties. Applications of colligative properties are very useful in day-to-day life. One of its examples is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator of automobiles. A solution M is prepared by mixing ethanol and water. Thus moel fraction of ethanol in the mixture is 0.9 . Given: Freezing point depression constant of water (K_(f)^("water")) = 1.86 K kg mol^(-1) Freezing point depression constant of ethanol (K_(f)^("ethanol")) = 2.0 K kg mol^(-1) Boiling point elevation constant of water (K_(b)^("water")) = 0.52 K kg mol^(-1) Boiling point elevation constant of ethanol (K_(b)^("ethanol")) = 1.2 K kg mol^(-1) Standard freezing point of water = 273 K Standard freezing point of ethanol = 155.7K Standard boiling point of water = 373 K Standard boiling point of ethanol = 351.5 K vapour pressure of pure water = 32.8 mm Hg Vapour pressure of pure ethanol = 40 mm Hg Molecualr weight of water = 18 g mol^(-1) Molecular weight of ethanol = 46 g mol^(-1) In asweering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative. The vapour pressure of the solution M is:
Some properties as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties. Applications of colligative properties are useful in day-to day life. Its example is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator of automobiles. A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9. Given : Freezing point depression constant of water (K_(f)^("water"))=1.86" K kg mol"^(-1) Freezing point depression constant of ethanol (K_(f)^("ethanol"))=2.0"K kg mol"^(-1) Boiling point elevation of water (K_(b)^("water"))=0.52" K kg mol"^(-1) Boiling point elevation constant of ethanol (K_(b)^("ethanol"))=1.2" K kg mol"^(-1) Standard freezing point of water = 273 K Standard freezing point of ethanol = 155.7 K Standard boiling point of water = 373 K Standard boiling point of ethanol = 251.5 K Vapour pressure of pure water = 32.8 mm Hg Vapour pressure of pure ethanol = 40 mm Hg Molecular weight of water = 18 g mol^(-1) Molecular weight of ethanol = 46 g mol^(-1) In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative. The vapour pressure of the solution M is
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Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties. Application of colligative properties are very useful in day to day life.one example is the use of ethylene glycol and water mixture as antifreezing liquid in the radiators of automobiles. A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in water is 0.9. Given, freezing point depression constant of water (K_(f) "water") = 1.86 Kg mol^(-1) . Freezing point depression constant of ethanol K_(f) (ethanol) = 2.0 K kg mol^(-1) Boiling point elevation constant of water K_(b) (water) = 0.52 K kg mol^(-1) Boiling point elevation constant of ethanol K_(b) (ethanol) = 1.2 K kg mol^(-1) Standard freezing point of water = 273 K Standard freezing point of ethanol = 155.7 K Standard boiling point of water = 373 K Standard boiling point of ethanol = 351.5 K Vapour pressure of pure water = 32.8 mm Hg Vapoure pressure of pure ethanol = 40 mm Hg Molecular weight of water = 18 g mol^(-1) Molecular weight of ethanol = 46 g mol^(-1) In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative. The vapour pressure of the solution M is