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Ice crystallises in hexagonal lattice ha...

Ice crystallises in hexagonal lattice having volume of unit cell is `132times10^(-24)cm^(3)`.If density is 0.92g `cm^(3)`at a given temperature, then number of water molecules per unit cell is

A

1

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
D
Density `(rho)=("Mass")/("Volume")`
Mass of n molecules of `H_(2)O`
in hcc packing `=(18n)/("No")=((18g " mol"^(-1))xxn)/((6.022xx10^(23)" mol"^(-1)))`
`(0.92 g " cm" ^(-3))=((18g " mol"^(-1))xxn)/((6.022xx10^(23)" mol"^(-1))xx(132xx10^(-24)cm^(3)))`
`n=((0.92 g cm^(3))xx(6.022xx10" mol"^(-1))xx(132xx10^(-24)cm^(3)))/((18g " mol"^(-1)))=4`
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Knowledge Check

  • Ice crystallises in a hexagonal lattice having a volume of the unit cell as 132xx10^(-24) cm^3 . If density of ice at the given temperature is 0.92 g cm^(-3) , then number of H_2O molecules per unit cell is

    A
    1
    B
    2
    C
    3
    D
    4

  • Ice crystallises in a hexagonal lattice having a volume of the unit cell as 132 xx 10^(-24) cm^(3) . If density of ice at the given temperature is 0.92 g cm^(-3) , the number of H_(2)O molecules per unit cell is

    A
    1
    B
    2
    C
    3
    D
    4

  • A element cystallizes in fcc lattice and edge length of unit cell is 400 pm. If density of unit cell is 11.2 g cm^(-3) , then atomic mass of the element is

    A
    215.6
    B
    431.2
    C
    107.8
    D
    98.6

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