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ZnS is not precipitated by passing H(2)S...

ZnS is not precipitated by passing `H_(2)S` in acidic medium but CuS is precipitated . The reason for it is

A

`K_(sp) CuS lt lt K_(sp) ZnS`

B

`K_(sp)CuS gt gt K_(sp) ZnS`

C

`K_(p) CuS =K_(sp) ZnS`

D

None of these

Text Solution

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The correct Answer is:
To understand why ZnS is not precipitated by passing H₂S in acidic medium while CuS is precipitated, we need to analyze the solubility product constant (Ksp) for both compounds and the conditions under which they precipitate. ### Step-by-Step Solution: 1. **Understanding Ksp**: - The solubility product constant (Ksp) is a measure of the solubility of a sparingly soluble salt. It is defined as the product of the molar concentrations of the ions in a saturated solution, each raised to the power of their coefficients in the balanced equation. - For ZnS: \[ K_{sp} = [Zn^{2+}][S^{2-}] \] - For CuS: \[ K_{sp} = [Cu^{2+}][S^{2-}] \] 2. **Comparing Ksp Values**: - The Ksp value for CuS is lower than that for ZnS. This means that CuS is less soluble in water compared to ZnS. - As a result, when H₂S is introduced into a solution containing Cu²⁺ ions, the ionic product (IP) of CuS exceeds its Ksp, leading to the precipitation of CuS. 3. **Effect of Acidic Medium**: - In an acidic medium, the concentration of H⁺ ions increases. This causes the equilibrium of the sulfide ions (S²⁻) to shift, as H⁺ ions react with S²⁻ to form H₂S. - The presence of H⁺ ions reduces the concentration of S²⁻ ions, which is essential for the precipitation of both ZnS and CuS. 4. **Precipitation of CuS**: - Since CuS has a lower Ksp, even a small concentration of S²⁻ ions can lead to the precipitation of CuS when H₂S is passed through the solution. - In contrast, the Ksp of ZnS is higher, meaning that a higher concentration of S²⁻ ions is required to initiate precipitation. In acidic conditions, the concentration of S²⁻ is too low to exceed the Ksp of ZnS, preventing its precipitation. 5. **Conclusion**: - Therefore, when H₂S is passed in an acidic medium, CuS precipitates due to its lower Ksp, while ZnS does not precipitate because the conditions do not allow for sufficient S²⁻ concentration to exceed its Ksp.

To understand why ZnS is not precipitated by passing H₂S in acidic medium while CuS is precipitated, we need to analyze the solubility product constant (Ksp) for both compounds and the conditions under which they precipitate. ### Step-by-Step Solution: 1. **Understanding Ksp**: - The solubility product constant (Ksp) is a measure of the solubility of a sparingly soluble salt. It is defined as the product of the molar concentrations of the ions in a saturated solution, each raised to the power of their coefficients in the balanced equation. - For ZnS: \[ K_{sp} = [Zn^{2+}][S^{2-}] \] ...
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Knowledge Check

  • The correct option(s) to distinguish nitrate salts of Mn^(2+) and Cu^(2+) taken separately is (Are) (1) Mn^(2+) shows the characteristic green colour in the flame test (2) only Cu^(2+) shows the the formation of precipitate by passing H_(2)S in acidic medium (3) only Mn^(2+) shows the formation of precipitate by passing H_(2)S in faintly basic medium (4) Cu^(2+)|"Cu has higher reduction potential then "Mn^(2+)|Mn (measured under similar conditions)

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