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The dissociation constants of two acids ...

The dissociation constants of two acids `HA_(1)` and `HA_(2)` are `3.0xx10^(-4)` and `1.8xx10^(-5)` respectively. The relative strengths of the acids will be approximately

A

`1:4`

B

`4:1`

C

`1:16`

D

`16:1`

Text Solution

Verified by Experts

The correct Answer is:
B
`("Strength of acid " HA_(1))/("Strength of acid " HA_(2))=sqrt((K_(1))/(K_(2)))`
`sqrt((3.0xx10^(-4))/(1.8 xx 10^(-5)))=(4)/(1)`
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