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sp^3 has s-character...

`sp^3` has s-character

A

`1//2`

B

`1//4`

C

`1//8`

D

1

Text Solution

Verified by Experts

The correct Answer is:
B
`sp^3` has 1/4 s character.
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(a) How do bond length and bond strength vary in the following cases? C-C, C=C, C-=C (b) Arrange the sp-,sp^(2-) and sp^(3) -hybridization in increasing order of: (i) bond length (ii) bond angle (iii) bond energy (iv) size of orbitals (v)s-character

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Smallest Ohat(S)O bond angle is found in :

Knowledge Check

  • Ahybrid orbital has 25% s-character and 75% p-character. To which type of hybridization it belongs

    A
    `sp^(3)`
    B
    `sp^(2)`
    C
    sp
    D
    `s^(2)p`

  • Which of the following hybridisation has maximum s-characters

    A
    `sp^(3)`
    B
    `sp^(2)`
    C
    `sp`
    D
    none of these

  • Statement I: d_(P-F) is greater than d_(P-Cl) in PF_2Cl_3 . Statement II: The axial orbital has no s character while equatorial orbital has 33.33% s character in trigonal bipyramidal geometry.

    A
    If both Statement I and Statement II are true and Statement II is the correct explanation of Statement I.
    B
    If both Statement I and Statement II are true but Statement II is not the correct explanation for Statement I.
    C
    If Statement I is true but Statement II is false.
    D
    If Statement I is false but Statement II is true.

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    According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Smallest Ohat(S)O bond angle is found in :

    According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Correct order of P-P bond length in the following compound is :

    According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Correct order of P-P bond length in the following compound is :

    According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Two elements X and Y combined together to form a covalent compound. If % p-character is found to be 80% in a orbital then the hybridised state of central atom X for the orbital is :

    According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Two elements X and Y combined together to form a covalent compound. If % p-character is found to be 80% in a orbital then the hybridised state of central atom X for the orbital is :

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