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The following initial rate data were obt...

The following initial rate data were obtained at 300K for the reactions:
`2A + B to C +D`

Deducethe rate law.

Text Solution

Verified by Experts

On compairing (I) and (II), [B] remains constant. Since on making [A] twice, the reaction rate becomes four times.
`(2.4 xx 10^(-2)//6 xx 10^(-2)=4)`, the order with respect to A is 2.
On compairing (I) and (III), [A] remains constant. Since on making [B] twice, the reaction rate becomes twice `(12 xx 10^(-2)//6 xx 10^(-2)=2)`, the order with respect to B is 1.
`therefore` Rate equation is: `r=k[A]^(2)[B]`
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Knowledge Check

  • Rate law for the reaction A + 2B to C is found to be

    A
    the same
    B
    doubled
    C
    quadrupled
    D
    halved

  • Form the data given below for the reaction: A to B to Products the rate law expression is:

    A
    Rate=k[A][B]
    B
    Rate=`k[A][B]^2`
    C
    Rate=`k[A]^2[B]^2`
    D
    Rate=`k[A]^2[B]`

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